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SQL扫描数据库中以前的记录_Sql_Sqlite - Fatal编程技术网

SQL扫描数据库中以前的记录

SQL扫描数据库中以前的记录,sql,sqlite,Sql,Sqlite,以桌子为例 Index Col_1 Col_2 Value_of_Interest Record_1 1 Record_2 2 . . . Record_N N Index Col_1 Col_2 Value_of_Interest Record_1 1 Ed Bill 1 Record_2 2 James Rob

以桌子为例

          Index    Col_1    Col_2   Value_of_Interest
Record_1    1
Record_2    2
   .
   .
   .
Record_N    N
          Index    Col_1    Col_2   Value_of_Interest
Record_1    1       Ed      Bill           1
Record_2    2      James    Rob            0
Record_3    3       Tom     Rob            1
Record_4    4      Bill     Rob            0
我想选择一组记录{Record_I},以便记录_I+1的列_1存在于{select Col_2 FROM table WHERE Index中 MySQL 5.5.32架构设置:

问题1:


你能用英语重新表述这个问题吗?哈哈,我会再解释一次。你为什么要使用MySQL?Oupsss…没有看到SQLFIDLE中有SQLite…但它是基本SQL…所以它可以工作…可能只是```
          Index    Col_1    Col_2   Value_of_Interest
Record_3    3       Tom     Rob            1
SELECT *
FROM MyTable AS T1
WHERE (SELECT Col_1
       FROM MyTable AS T2
       WHERE T2.Index = T1.Index + 1
      ) IN (SELECT Col_2
            FROM MyTable AS T3
            WHERE T3.Index < T1.Index)
CREATE TABLE Table1
    (`Index` int, `Col_1` varchar(5), `Col_2` varchar(4), `Value_of_Interest` int)
;

INSERT INTO Table1
    (`Index`, `Col_1`, `Col_2`, `Value_of_Interest`)
VALUES
    (1, 'Ed', 'Bill', 1),
    (2, 'James', 'Rob', 0),
    (3, 'Tom', 'Rob', 1),
    (4, 'Bill', 'Rob', 0)
;
SELECT t1.`Index`, t1.Col_1, t1.Col_2, t1.Value_of_Interest
FROM Table1 t1
WHERE t1.`index` =
(SELECT t2.`index`-1
FROM Table1 t2
WHERE t2.Col_1 IN 
     (SELECT Col_2 FROM Table1 t3 WHERE t3.`Index` < t2.`Index`))
| INDEX | COL_1 | COL_2 | VALUE_OF_INTEREST |
|-------|-------|-------|-------------------|
|     3 |   Tom |   Rob |                 1 |