Sql SSI删除不需要的字符

如何在文本之间删除SSI中不需要的字符

i、 我们有这样的数据

2134;#Adam Connor (aconnor),21987;#Tatanka Wabe (Twabe);# 

当它来源于sharepoint时。我尝试了子字符串、替换等，但无法删除名称之间的数字

我希望输出为

Adam Connor, Tatanka Kale

您可以使用正则表达式 注：VB.NET中的代码

您需要提取

#

和

（

---

SSIS版本-使用脚本组件 您可以使用脚本组件通过正则表达式实现这一点：

假设

Column0

是输入列，

outColumn

是输出列

导入系统
导入系统数据
导入系统。数学
导入Microsoft.SqlServer.Dts.Pipeline.Wrapper
导入Microsoft.SqlServer.Dts.Runtime.Wrapper
导入System.Text.RegularExpressions
_  
_  
公共类ScriptMain
继承用户组件
公共覆盖子Input0\u进程InputRow（ByVal行作为Input0Buffer）
如果不是，则Row.Column0\u为空，并且也为空_
不是String.IsNullOrEmpty（Row.Column0.Trim）然后
作为字符串的Dim strContent=Row.Column0
Dim mc As MatchCollection=Regex.Matches（strContent），（？如果示例数据表示模式，并且您对表值函数开放

不久前，由于厌倦了提取字符串（左、右、子字符串、charindex、patindex等），我修改了parse函数以接受两个不相似的参数

示例

Declare @YourTable table (ID int,SomeCol varchar(max))
Insert Into @YourTable values
(1,'2134;#Adam Connor (aconnor),21987;#Tatanka Wabe (Twabe);#')

Select A.ID
      ,B.*
 From  @YourTable A
 Cross Apply (
                Select NewVal = Stuff((Select ', ' +ltrim(rtrim(RetVal)) 
                                         From [dbo].[tvf-Str-Extract](A.SomeCol,'#','(') 
                                         For XML Path ('')
                                      ),1,2,'')
             ) B

返回

ID  NewVal
1   Adam Connor, Tatanka Wabe

感兴趣的功能

CREATE FUNCTION [dbo].[tvf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table 
As
Return (  

with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
       cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
       cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
       cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)

Select RetSeq = Row_Number() over (Order By N)
      ,RetPos = N
      ,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1) 
 From  (
        Select *,RetVal = Substring(@String, N, L) 
         From  cte4
       ) A
 Where charindex(@Delimiter2,RetVal)>1

)
/*
Max Length of String 1MM characters

Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[tvf-Str-Extract] (@String,'[[',']]')
*/

注意：

如果你只是跑

Declare @YourTable table (ID int,SomeCol varchar(max))
Insert Into @YourTable values
(1,'2134;#Adam Connor (aconnor),21987;#Tatanka Wabe (Twabe);#')

Select A.ID
      ,B.*
 From  @YourTable A
 Cross Apply [dbo].[tvf-Str-Extract](A.SomeCol,'#','(')  B

你会得到

ID  RetSeq  RetPos  RetVal
1   1       7       Adam Connor 
1   2       36      Tatanka Wabe 

在提出第一个问题之前，建议阅读，以了解更多关于提出好问题、接受答案和其他网站规则的信息。此外，还可以获得“知情”徽章。
CREATE FUNCTION [dbo].[tvf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table 
As
Return (  

with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
       cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
       cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
       cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)

Select RetSeq = Row_Number() over (Order By N)
      ,RetPos = N
      ,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1) 
 From  (
        Select *,RetVal = Substring(@String, N, L) 
         From  cte4
       ) A
 Where charindex(@Delimiter2,RetVal)>1

)
/*
Max Length of String 1MM characters

Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[tvf-Str-Extract] (@String,'[[',']]')
*/

Declare @YourTable table (ID int,SomeCol varchar(max))
Insert Into @YourTable values
(1,'2134;#Adam Connor (aconnor),21987;#Tatanka Wabe (Twabe);#')

Select A.ID
      ,B.*
 From  @YourTable A
 Cross Apply [dbo].[tvf-Str-Extract](A.SomeCol,'#','(')  B

ID  RetSeq  RetPos  RetVal
1   1       7       Adam Connor 
1   2       36      Tatanka Wabe