如何仅显示可以'；t登录并消除SQL中的其余部分

我有一个包含以下列和数据的表，我正在尝试编写一个查询，以便它仅在用户未登录时显示：

SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'password reset' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'logged in' as verb
union all
SELECT 'Kevin' as First_name, 'Owens' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Kevin' as First_name, 'Owens' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Kevin' as First_name, 'Owens' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all                   
SELECT 'Kevin' as First_name, 'Owens' as Last_Name, getdate() as timestamp, 'password reset' as verb
union all                   
SELECT 'Kevin' as First_name, 'Owens' as Last_Name, getdate() as timestamp, 'logged in' as verb
union all
SELECT 'Kevin' as First_name, 'Owens' as Last_Name, getdate() as timestamp, 'logged in' as verb
union all
SELECT 'Roman' as First_name, 'Reigns' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all                   
SELECT 'Roman' as First_name, 'Reigns' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all                   
SELECT 'Roman' as First_name, 'Reigns' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Roman' as First_name, 'Reigns' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all                   
SELECT 'Roman' as First_name, 'Reigns' as Last_Name, getdate() as timestamp, 'password reset' as verb
union all
SELECT 'Roman' as First_name, 'Reigns' as Last_Name, getdate() as timestamp, 'password reset' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'tried log in' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'password reset' as verb
union all
SELECT 'Seth' as First_name, 'Rollins' as Last_Name, getdate() as timestamp, 'tried log in' as verb

这为我提供了以下输出：

First_name  Last_Name   timestamp              verb
Seth        Rollins 2017-02-20 15:28:55.660 tried log in
Seth        Rollins 2017-02-20 15:28:55.660 tried log in
Seth        Rollins 2017-02-20 15:28:55.660 password reset
Seth        Rollins 2017-02-20 15:28:55.660 logged in
Kevin       Owens   2017-02-19 15:28:55.660 tried log in
Kevin       Owens   2017-02-19 15:28:55.660 tried log in
Kevin       Owens   2017-02-19 15:28:55.660 tried log in
Kevin       Owens   2017-02-20 15:28:55.660 password reset
Kevin       Owens   2017-02-20 15:28:55.660 logged in
Kevin       Owens   2017-02-21 15:28:55.660 logged in
Roman       Reigns  2017-02-20 15:28:55.660 tried log in
Roman       Reigns  2017-02-20 15:28:55.660 tried log in
Roman       Reigns  2017-02-20 15:28:55.660 tried log in
Roman       Reigns  2017-02-20 15:28:55.660 tried log in
Roman       Reigns  2017-02-20 15:28:55.660 password reset
Roman       Reigns  2017-02-20 15:28:55.660 password reset
Seth        Rollins 2017-02-21 15:28:55.660 tried log in
Seth        Rollins 2017-02-21 15:28:55.660 tried log in
Seth        Rollins 2017-02-21 15:28:55.660 tried log in

我目前正在尝试编写一个查询，因此它只显示Roman未成功登录时的统治次数，以便显示他尝试登录的次数以及密码重置。不应显示Seth Rollins的第一组结果，但应显示2017年2月21日的结果，因为他尚未成功登录

我目前正试图找出编写此查询的最佳方法

我的预期结果如下：

First_Name, Last_Name, Count of TriedLogIn, Count of PasswordResets
Roman        Reigns            4                        2
Seth         Rollins           3                       null

---

Seth Rollins名字出现的原因是，在成功登录20/02之后，他自该日期（21/02）起就没有成功登录过。成功登录后，计数将重置回0。

使用

不存在的

select *
from users u1
where verb = 'tried log in'
and not exists
(
select 1
from users u2
where u1.firstname = u2.firstname 
and u1.lastname = u2.lastname
and u2.verb = 'logged in'
)

对于该特定用户，使用
case
表达式进行条件计数：

select count(case when verb = 'tried log in' then 1 end) as loginfailures,
       count(case when verb = 'password reset' then 1 end) as passwordresets
from tablename
where First_name = 'Roman' and Last_name = 'Reigns'

如果您想要相同的信息，但对于所有用户，请按进行分组：

select First_name, Last_name,
       count(case when verb = 'tried log in' then 1 end) as loginfailures,
       count(case when verb = 'password reset' then 1 end) as passwordresets
from tablename
group by First_name, Last_name

谢谢你的回答，但我想这个问题不会起作用，因为赛斯·罗林斯在重置密码后第一次登录，但一天后遇到了困难。在您提到的代码中，这意味着2017年2月20日的尝试登录和密码重置也将被计入计数的一部分。希望这有点道理。@VGJ，你能编辑你的问题并添加预期的结果（格式文本）吗？谢谢你的回答，但这个查询不会像预期的那样工作-我也在问题中包含了预期的结果。