SQL Server:使用附加数据获取一系列值之间的最大值
大多数人想要最大值,但我需要一个范围内的最大值加上额外的数据。例如,我有一个团队及其经理及其经理id的列表。我查看了google/stackoverflow,但大多数人只想要最大值,但我也需要其他列,这就是我问这个问题的原因 表1:SQL Server:使用附加数据获取一系列值之间的最大值,sql,sql-server-2008,aggregate,Sql,Sql Server 2008,Aggregate,大多数人想要最大值,但我需要一个范围内的最大值加上额外的数据。例如,我有一个团队及其经理及其经理id的列表。我查看了google/stackoverflow,但大多数人只想要最大值,但我也需要其他列,这就是我问这个问题的原因 表1: team mgr_level mgr_id ----------------------- aa 1 111 aa 2 222 aa 3 333 bb 1 1
team mgr_level mgr_id
-----------------------
aa 1 111
aa 2 222
aa 3 333
bb 1 111
bb 2 222
cc 1 111
cc 2 222
cc 3 444
cc 4 888
employee emp_id team
------------------------------
smith, mary 23 aa
jones, john 34 bb
ramjet, roger 98 cc
james, adam 111 mgr_team
green, rachel 222 mgr_team
bruin, breezly 333 mgr_team
runner, road 444 mgr_team
potter, harry 888 mgr_team
表2:
team mgr_level mgr_id
-----------------------
aa 1 111
aa 2 222
aa 3 333
bb 1 111
bb 2 222
cc 1 111
cc 2 222
cc 3 444
cc 4 888
employee emp_id team
------------------------------
smith, mary 23 aa
jones, john 34 bb
ramjet, roger 98 cc
james, adam 111 mgr_team
green, rachel 222 mgr_team
bruin, breezly 333 mgr_team
runner, road 444 mgr_team
potter, harry 888 mgr_team
我需要使用其他数据(团队和经理id)选择介于222和444之间的最大值(经理id)
结果如下所示。有没有办法一步完成而不是两步完成
name team primary_mgr_id manager_name
-----------------------------------------------
smith, mary aa 333 bruin, breezly
jones, john bb 222 green, rachel
ramjet, roger cc 444 runner, road
我尝试了这个方法,SQL Server不断为每个名称返回多行:我做错了什么
select max(mgr_id) as [primary_mgr_id], t2.employee, t1.mgr_id
from table2 t2
inner join table1 t1 on t2.team = t2.team
group by t2.employee, t1.mgr_id
谢谢你的帮助。
斯文这就是你要找的人吗
SELECT
employee AS name, team, max_mgr_id AS primary_mgr_id, t3.employee as manager_name
FROM
table2 t2
JOIN (
SELECT team, MAX(mgr_id) AS max_mgr_id
FROM table1
) t1 ON t2.team = t1.team
JOIN table2 t3 ON t3.emp_id = t1.max_mgr_id AND t3.team = 'mgr_team'
一个选项是借助行号()
返回
Name Team primary_mgr_id manager_name
smith, mary aa 333 bruin, breezly
jones, john bb 222 green, rachel
ramjet, roger cc 444 runner, road
另一个选项是使用交叉应用
我会使用
外部应用
select t2.*, t1.mgr_id as primary_mgr_id , t1.name as manager_name
from table2 t2 outer apply
(select t1.mgr_id, tt2.name
from table1 t1 join
table2 tt2
on t1.mgr_id = tt2.emp_id
where t1.team = t2.team and
t1.mgr_id between 222 and 444
order by t1.mgr_id desc
) t1;
我加上去了!谢谢,我忘记加了