SQL显示计数为0时的月份

我想知道是否有人能帮我

下面的SQL查询将其缩短为大型联合查询

  SELECT [  Month   ],
sum(total) 
 from
(select datename(month,Resolved1Date) as '  Month   ',
COUNT(case when 
fileDescription not like 'test%' 
and Issue1Description ='Escalated' then 0 else 1 end)   as 'total'   
FROM         complaint_1 WITH (nolock) INNER JOIN
             Case WITH (nolock) ON Case.ref = complaint_1.ref 
WHERE     
Resolved1Date >=DATEADD(yy,DATEDIFF(yy,0,GETDATE()),0)
Resolved1Date  <= dateadd(mm,datediff(mm,0,getdate()),0)
group by datename(month,Resolved1Date), datepart(month, Resolved1Date)
)x                     
group by  [  Month   ]
order by  [  Month   ] desc

---

有人能给我指引正确的方向吗？

您可以创建临时表并从中左连接

大概是这样的：

DECLARE @Helper TABLE 
(
  TheDate datetime
)

DECLARE @StartDate datetime
SELECT @StartDate = '01.01.2015'

WHILE @StartDate < DATEADD(day,7,GETDATE())
BEGIN
  INSERT INTO @Helper (Thedate) VALUES (@StartDate)

  SELECT @StartDate = DATEADD(MONTH, 1, @StartDate)

END

---

我希望它能有所帮助。

在from子句中创建一组月份作为第一个表，并将您的查询加入到这个表中。然后你每个月都会得到一个结果。 我在财务报告方面也有类似的问题，我需要所有月份和财年的结果。 我使用了DATENAME函数来确保结果与您的查询一致。 如果您希望数据按月份顺序为一月-二月-三月，您可能不希望按月份排序，因为这是按字母顺序排列的，您需要包含一个排序字段

SELECT M.[  Month  ] AS [  Month  ]
      ,SUM(ISNULL(x.total,0)) AS [Total] -- x.total will be null for months with no transactions.
  FROM -- Set of Months (need one record for each month)
     (SELECT * FROM (VALUES(DATENAME(month,'2015-01-01'),1)
                          ,(DATENAME(month,'2015-02-01'),2)
                          ,(DATENAME(month,'2015-03-01'),3)
                          ,(DATENAME(month,'2015-04-01'),4)
                          ,(DATENAME(month,'2015-05-01'),5)
                          ,(DATENAME(month,'2015-06-01'),6)
                          ,(DATENAME(month,'2015-07-01'),7)
                          ,(DATENAME(month,'2015-08-01'),8)
                          ,(DATENAME(month,'2015-09-01'),9)
                          ,(DATENAME(month,'2015-10-01'),10)
                          ,(DATENAME(month,'2015-11-01'),11)
                          ,(DATENAME(month,'2015-12-01'),12)) AS Mnth("  Month  ",MnthSort)) AS M
LEFT OUTER JOIN  -- Your from clause goes here.
     (SELECT * 
        FROM (VALUES (DATENAME(month,'2015-01-01'),5)
                    ,(DATENAME(month,'2015-02-01'),4)
                    ,(DATENAME(month,'2015-02-01'),6)
                    ,(DATENAME(month,'2015-03-01'),7)
                    ,(DATENAME(month,'2015-04-01'),0)
                    ,(DATENAME(month,'2015-05-01'),1)
                    ,(DATENAME(month,'2015-05-01'),1)
              ) AS data("  Month  ","total")) x ON x.[  Month  ] = M.[  Month  ]
GROUP BY M.[  Month  ], M.MnthSort
ORDER BY M.MnthSort

我在SQLServer2008-R1上运行了这个

查询中from子句的第一部分以表格格式定义月份集，每个月返回一行运行此命令以查看结果：

SELECT * FROM (VALUES(DATENAME(month,'2015-01-01'),1)
                     ,(DATENAME(month,'2015-02-01'),2)
                     ,(DATENAME(month,'2015-03-01'),3)
                     ,(DATENAME(month,'2015-04-01'),4)
                     ,(DATENAME(month,'2015-05-01'),5)
                     ,(DATENAME(month,'2015-06-01'),6)
                     ,(DATENAME(month,'2015-07-01'),7)
                     ,(DATENAME(month,'2015-08-01'),8)
                     ,(DATENAME(month,'2015-09-01'),9)
                     ,(DATENAME(month,'2015-10-01'),10)
                     ,(DATENAME(month,'2015-11-01'),11)
                     ,(DATENAME(month,'2015-12-01'),12)) AS Mnth("  Month  ",MnthSort)

后面的左外部联接用于将查询结果链接到每个月，因此每个月都会得到一个总数。使用外部联接是因为没有每个月的合计

使用上面的sql进行的查询如下：

SELECT M.[  Month  ] AS [  Month  ]
      ,SUM(ISNULL(x.total,0)) AS [Total] -- x.total will be null for months with no transactions.
  FROM -- Set of Months (January - December), ensures one record for each month
     (SELECT * FROM (VALUES(DATENAME(month,'2015-01-01'),1)
                          ,(DATENAME(month,'2015-02-01'),2)
                          ,(DATENAME(month,'2015-03-01'),3)
                          ,(DATENAME(month,'2015-04-01'),4)
                          ,(DATENAME(month,'2015-05-01'),5)
                          ,(DATENAME(month,'2015-06-01'),6)
                          ,(DATENAME(month,'2015-07-01'),7)
                          ,(DATENAME(month,'2015-08-01'),8)
                          ,(DATENAME(month,'2015-09-01'),9)
                          ,(DATENAME(month,'2015-10-01'),10)
                          ,(DATENAME(month,'2015-11-01'),11)
                          ,(DATENAME(month,'2015-12-01'),12)) AS Mnth("  Month  ",MnthSort)) AS M
LEFT OUTER JOIN  -- Your Query included from here...
    (SELECT datename(month,Resolved1Date) as '  Month   ',
            COUNT(CASE WHEN fileDescription NOT LIKE 'test%' 
                        AND Issue1Description ='Escalated' THEN 0 ELSE 1
                  END) as 'total'   
       FROM complaint_1 WITH (nolock)
            INNER JOIN Case WITH (nolock) ON Case.ref = complaint_1.ref 
      WHERE     
            Resolved1Date >=DATEADD(yy,DATEDIFF(yy,0,GETDATE()),0)
            Resolved1Date  <= dateadd(mm,datediff(mm,0,getdate()),0)
      group by datename(month,Resolved1Date), datepart(month, Resolved1Date)
     ) x on x.[  Month  ] = M.[  Month  ]

GROUP BY M.[  Month  ], M.MnthSort
ORDER BY M.MnthSort

---

您不能只为ResolvedDate=0添加另一个WHERE子句吗？您应该格式化查询。您还应该修正逻辑。例如，countcase中的case语句没有任何作用。你也应该用你正在使用的数据库来标记这个问题。删除case语句无助于我的目标，我认为问题在于计数，因为我在计算一个日期字段，然后说明sate字段在两个值之间的位置，如果不匹配，我需要它将一个月显示为0。谢谢你的帖子@nxb，你能解释一下，在from子句中创建一组月份作为第一个表是什么意思吗？我对SQL还很陌生，这让我开始发疯了！编辑帖子回答问题，希望更清楚。啊，明白了，我已经注释掉了“左外连接”并输入了我的查询，并且收到了错误的语法消息。我不明白它是用来把我的查询结果和月份联系起来的，现在有意义了。感谢您的帮助@nxb:-非常感谢

SELECT M.[  Month  ] AS [  Month  ]
      ,SUM(ISNULL(x.total,0)) AS [Total] -- x.total will be null for months with no transactions.
  FROM -- Set of Months (January - December), ensures one record for each month
     (SELECT * FROM (VALUES(DATENAME(month,'2015-01-01'),1)
                          ,(DATENAME(month,'2015-02-01'),2)
                          ,(DATENAME(month,'2015-03-01'),3)
                          ,(DATENAME(month,'2015-04-01'),4)
                          ,(DATENAME(month,'2015-05-01'),5)
                          ,(DATENAME(month,'2015-06-01'),6)
                          ,(DATENAME(month,'2015-07-01'),7)
                          ,(DATENAME(month,'2015-08-01'),8)
                          ,(DATENAME(month,'2015-09-01'),9)
                          ,(DATENAME(month,'2015-10-01'),10)
                          ,(DATENAME(month,'2015-11-01'),11)
                          ,(DATENAME(month,'2015-12-01'),12)) AS Mnth("  Month  ",MnthSort)) AS M
LEFT OUTER JOIN  -- Your Query included from here...
    (SELECT datename(month,Resolved1Date) as '  Month   ',
            COUNT(CASE WHEN fileDescription NOT LIKE 'test%' 
                        AND Issue1Description ='Escalated' THEN 0 ELSE 1
                  END) as 'total'   
       FROM complaint_1 WITH (nolock)
            INNER JOIN Case WITH (nolock) ON Case.ref = complaint_1.ref 
      WHERE     
            Resolved1Date >=DATEADD(yy,DATEDIFF(yy,0,GETDATE()),0)
            Resolved1Date  <= dateadd(mm,datediff(mm,0,getdate()),0)
      group by datename(month,Resolved1Date), datepart(month, Resolved1Date)
     ) x on x.[  Month  ] = M.[  Month  ]

GROUP BY M.[  Month  ], M.MnthSort
ORDER BY M.MnthSort