String 通过串口向Arduino发送字符串
我目前正在尝试向我的Arduino云发送一个字符串,并试图让它根据我发送的内容回复 我在这里学习了一些代码的框架,并一直在尝试它,但除了显示“就绪”的串行监视器之外,我无法再进一步了 代码是:String 通过串口向Arduino发送字符串,string,serial-port,arduino,String,Serial Port,Arduino,我目前正在尝试向我的Arduino云发送一个字符串,并试图让它根据我发送的内容回复 我在这里学习了一些代码的框架,并一直在尝试它,但除了显示“就绪”的串行监视器之外,我无法再进一步了 代码是: //declace a String to hold what we're inputting String incomingString; void setup() { //initialise Serial communication on 9600 baud Serial.begin(96
//declace a String to hold what we're inputting
String incomingString;
void setup() {
//initialise Serial communication on 9600 baud
Serial.begin(9600);
while(!Serial);
//delay(4000);
Serial.println("Ready!");
// The incoming String built up one byte at a time.
incomingString = "";
}
void loop () {
// Check if there's incoming serial data.
if (Serial.available() > 0) {
// Read a byte from the serial buffer.
char incomingByte = (char)Serial.read();
incomingString += incomingByte;
// Checks for null termination of the string.
if (incomingByte == '\0') {
// ...do something with String...
if(incomingString == "hello") {
Serial.println("Hello World!");
}
incomingString = "";
}
}
}
谁能给我指出正确的方向吗
谢谢我怀疑问题在于,当您这样做时,您正在将空终止符添加到字符串的末尾:incomingString+=incomingByte。当您使用字符串对象而不是原始字符*字符串时,您不需要这样做。对象将自行处理终止 结果是您的if条件有效地做到了这一点:if hello\0==hello。。。。显然它们不相等,所以条件总是失败的 我相信解决方案只是确保如果字节为null,则不会追加该字节。尝试以下方法:
String IncomingData = "";
String Temp = "";
char = var;
void setup()
{
Serial.begin(9600);
//you dont have to use it but if you want
// if(Serial)
{
Serial.println("Ready");
}
//or
while(!Serial)
{delay(5);}
Serial.println("Ready");
void loop()
{
while(Serial.available())
{
var = Serial.read();
Temp = String(var);
IncomingData+= Temp;
//or
IncomingData.concat(Temp);
// you can try
IncomindData += String(var);
}
Serial.println(IncomingData);
IncomingData = "";
}
同意根据这一点,@adeptionvention应该替换incomingString+=incomingByte;if incomingByte=='\0'{和if incomeByte incomingString+=incomingByte;else{。