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Swift中双精度的未签名长-长_Swift_Double_Unsigned Long Long Int - Fatal编程技术网

Swift中双精度的未签名长-长

Swift中双精度的未签名长-长,swift,double,unsigned-long-long-int,Swift,Double,Unsigned Long Long Int,我曾在Objective-C中使用以下内容: double currentTime = CFAbsoluteTimeGetCurrent(); // self.startTime is called before, like // self.startTime = CFAbsoluteTimeGetCurrent(); double elapsedTime = currentTime - self.startTime; // Convert the double to milli

我曾在Objective-C中使用以下内容:

double currentTime = CFAbsoluteTimeGetCurrent();

// self.startTime is called before, like     
// self.startTime = CFAbsoluteTimeGetCurrent();

double elapsedTime = currentTime - self.startTime;

// Convert the double to milliseconds
unsigned long long milliSecs = (unsigned long long)(elapsedTime * 1000);
在我的swift代码中,我目前有:

let currentTime: Double = CFAbsoluteTimeGetCurrent()
let elapsedTime: Double = currentTime - startTime

let milliSecs: CUnsignedLongLong = elapsedTime * 1000
但是我得到了一个错误,
double
不能转换为
CUnsignedLongLong
,这是有道理的。有没有办法像在Objective-C中那样施展它?有办法解决这个问题吗

有没有一种方法可以像在Objective C中那样施展它?有办法解决这个问题吗


CUnsignedLongLong
在标准库中定义为:

typealias CUnsignedLongLong = UInt64
因此,要将
Double
转换为
CUnsignedLongLong
,需要使用创建
CUnsignedLongLong
的新实例

CUnsignedLongLong(elapsedTime * 1000)


Swift不允许隐式类型转换。使用构造函数为其类型创建值

let milliSecs = CFUnsignedLongLong(elapsedTime * 1000)
CUnsignedLongLong(elapsedTime * 1000)
UInt64(elapsedTime * 1000)
let milliSecs = CFUnsignedLongLong(elapsedTime * 1000)