在Swift中的TableView之间传递数据

我的项目中运行了两个tableView。我正在尝试将第一个tableView单元格数据传递（复制）到第二个tableView。我使用tableView行操作方法传递数据。下面的部分代码

第一个VC:

var tableView: UITableView!
var DataArray = ["Bus","Helicopter","Truck","Boat","Bicycle","Motorcycle","Plane","Train","Car","S    cooter","Caravan"]
var sendSelectedData = NSString()

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {

let copyAction = UITableViewRowAction(style: UITableViewRowActionStyle.normal, title: "Pass Data") { (UITableViewRowAction, NSIndexPath) -> Void in

print("Button Pressed") // Xcode Console prints **Button Pressed** when swipe action performed.

self.performSegue(withIdentifier: "send", sender: self)

 }

return [copyAction]
 }


func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    self.performSegue(withIdentifier: "send", sender: self)
    // segue.destination as! tableController

    let indexPath = tableView.indexPathForSelectedRow
    let currentCell =  tableView.cellForRow(at: indexPath!)!
    self.sendSelectedData = (currentCell.textLabel?.text)! as String as NSString

    let viewController = segue.destination as! tableController
    viewController.labelcell = ([self.sendSelectedData as String])
    print(self.sendSelectedData)  // no result
}

var labelcell = [String]()

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    var cell = tableView.dequeueReusableCell(withIdentifier: textCellIdentifier, for: indexPath as IndexPath) as UITableViewCell


    cell.textLabel?.text = labelcell[indexPath.row] as? String

    tableView.reloadData()

    return cell
}

第二个VC:

var tableView: UITableView!
var DataArray = ["Bus","Helicopter","Truck","Boat","Bicycle","Motorcycle","Plane","Train","Car","S    cooter","Caravan"]
var sendSelectedData = NSString()

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {

let copyAction = UITableViewRowAction(style: UITableViewRowActionStyle.normal, title: "Pass Data") { (UITableViewRowAction, NSIndexPath) -> Void in

print("Button Pressed") // Xcode Console prints **Button Pressed** when swipe action performed.

self.performSegue(withIdentifier: "send", sender: self)

 }

return [copyAction]
 }


func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    self.performSegue(withIdentifier: "send", sender: self)
    // segue.destination as! tableController

    let indexPath = tableView.indexPathForSelectedRow
    let currentCell =  tableView.cellForRow(at: indexPath!)!
    self.sendSelectedData = (currentCell.textLabel?.text)! as String as NSString

    let viewController = segue.destination as! tableController
    viewController.labelcell = ([self.sendSelectedData as String])
    print(self.sendSelectedData)  // no result
}

var labelcell = [String]()

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    var cell = tableView.dequeueReusableCell(withIdentifier: textCellIdentifier, for: indexPath as IndexPath) as UITableViewCell


    cell.textLabel?.text = labelcell[indexPath.row] as? String

    tableView.reloadData()

    return cell
}

---

上面的代码看起来像是将数据传递给我的第二个VC（segue）。但是，我只得到了一个空的tableview。

测试后，结果表明，您使用了一个不正确的

prepareForSegue

函数。您没有使用“prepareforsgue”，而是创建了一个名为

prepareforsgue

的函数，因为Swift 3中的语法已更改。这个将被调用，您可以传递数据

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "send" {

        let selectedIndex = sender as! NSIndexPath
        let currentCell =  tableView.cellForRow(at: selectedIndex as IndexPath)! as! Cell
        self.sendSelectedData = (currentCell.label?.text)! as String as NSString

        print(self.sendSelectedData) // till here it worked for me - it is filled with my label.text
        // I don't know what this is "viewController.labelcell", so you have to to know how to go on from here on

        viewController.labelcell = ([self.sendSelectedData as String])           
    }
}

此外，您还需要传递索引XPath：

self.performSegue(withIdentifier: "send", sender: indexPath)

正是这样:

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {

    let copyAction = UITableViewRowAction(style: UITableViewRowActionStyle.normal, title: "Pass Data") { (UITableViewRowAction, NSIndexPath) -> Void in

        print("editActionsForRowAt called") // Xcode Console prints **Button Pressed** when swipe action performed.
        self.performSegue(withIdentifier: "send", sender: indexPath)

    }

    return [copyAction]
}

这在我的测试项目中起了作用

---

还要注意：

Cell

是我创建的

UITableViewCell

的自定义子类，label是我测试项目标签元素的

UIOutlet

。

为什么要调用

self.performsgue（标识符：“send”，发送者：nil）

内部准备segue？可能是@Nirav D的重复。谢谢我把发件人改成了self。仍然没有结果。@DavidSeek我已经看过你的链接，我在论坛上也看到了类似的问题。所有这些问题只解释了如何将数据传递给detailview控制器，而不是电视。您是否发现我的代码有任何错误。。。。thanks@DavidSeek此打印将被称为致命错误：在tableView.indexPathForSelectedRow中展开可选值（lldb）时意外发现nil。