如何在Swift中使用词典?

如何在Swift中使用词典?,swift,dictionary,tableview,swift-dictionary,Swift,Dictionary,Tableview,Swift Dictionary,我创建了字典,如下所示 let bookList = [ ["title" : "Harry Potter", "author" : "Joan K. Rowling" "image" : image // UIImage is added. ], ["title" : "Twilight", "author" : " Stephenie Meyer", "image" : image ], ["title"

我创建了字典,如下所示

   let bookList = [
    ["title" : "Harry Potter",
     "author" : "Joan K. Rowling"
     "image" : image // UIImage is added.
    ],
    ["title" : "Twilight",
     "author" : " Stephenie Meyer",
     "image" : image
    ],
    ["title" : "The Lord of the Rings",
     "author" : "J. R. R. Tolkien",
     "image" : image]
我想用这个书单做一个表视图

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        guard let cell = tableView.dequeueReusableCell(withIdentifier: "listCell") as? ListCell else { return UITableViewCell() }
        let book = bookList[indexPath.row]

        cell.configureCell(title: book.???, author: ???, bookImage: ???)
        return cell
    }

我应该如何使用字典的值和键来配置单元格?

强烈建议使用自定义结构而不是字典

struct Book {
   let title : String
   let author : String
   let image : UIImage
}

var bookList = [Book(title: "Harry Potter", author: "Joan K. Rowling", image: image),
                Book(title: "Twilight", author: "Stephenie Meyer", image: image),
                Book(title: "The Lord of the Rings", author: "J. R. R. Tolkien", image: image)]
最大的好处是您有不同的非可选类型,而不需要任何类型转换

let book = bookList[indexPath.row]
cell.configureCell(title: book.title, author: book.author, bookImage: book.image)

此外,我要声明
configureCell

func configureCell(book : Book)
并通过

cell.configureCell(book: bookList[indexPath.row])

然后,您可以将结构的成员直接分配给
configureCell

中的标签。强烈建议使用自定义结构而不是字典

struct Book {
   let title : String
   let author : String
   let image : UIImage
}

var bookList = [Book(title: "Harry Potter", author: "Joan K. Rowling", image: image),
                Book(title: "Twilight", author: "Stephenie Meyer", image: image),
                Book(title: "The Lord of the Rings", author: "J. R. R. Tolkien", image: image)]
最大的好处是您有不同的非可选类型,而不需要任何类型转换

let book = bookList[indexPath.row]
cell.configureCell(title: book.title, author: book.author, bookImage: book.image)

此外,我要声明
configureCell

func configureCell(book : Book)
并通过

cell.configureCell(book: bookList[indexPath.row])

然后,您可以将结构的成员直接分配给
configureCell

中的标签。在这里,字典不是您最好的结构

字典的问题是,您必须处理类型转换(因为您的字典是
[String:Any]
),并处理字典查找是可选的,因为可能缺少键

您可以做(不推荐):

看到这有多痛苦了吗

相反,请使用自定义的
struct
来表示您的书籍:

struct Book {
    var title: String
    var author: String
    var image: UIImage
}


let bookList = [
    Book(
        title : "Harry Potter",
        author : "Joan K. Rowling",
        image : image // UIImage is added.
    ),
    Book(
        title : "Twilight",
        author : " Stephenie Meyer",
        image : image
    ),
    Book(
        title : "The Lord of the Rings",
        author : "J. R. R. Tolkien",
        image : image
    )
]
然后,您的配置就变成:

cell.configureCell(title: book.title, author: book.author, bookImage: book.image)

字典不是你最好的结构

字典的问题是,您必须处理类型转换(因为您的字典是
[String:Any]
),并处理字典查找是可选的,因为可能缺少键

您可以做(不推荐):

看到这有多痛苦了吗

相反,请使用自定义的
struct
来表示您的书籍:

struct Book {
    var title: String
    var author: String
    var image: UIImage
}


let bookList = [
    Book(
        title : "Harry Potter",
        author : "Joan K. Rowling",
        image : image // UIImage is added.
    ),
    Book(
        title : "Twilight",
        author : " Stephenie Meyer",
        image : image
    ),
    Book(
        title : "The Lord of the Rings",
        author : "J. R. R. Tolkien",
        image : image
    )
]
然后,您的配置就变成:

cell.configureCell(title: book.title, author: book.author, bookImage: book.image)

的确更令人信服的是,当我们两个人说出来时,这是一个值得考虑的想法。更令人信服的是,当我们两个人说出来时,这是一个值得考虑的想法。