Swift UIC应用程序未打开url
我从一个结构中获取URL并将其发送到一个Swift UIC应用程序未打开url,swift,url,uigesturerecognizer,uiapplication,Swift,Url,Uigesturerecognizer,Uiapplication,我从一个结构中获取URL并将其发送到一个uitappostation,我尝试打印它(它打印URL),但它不想实际打开URL @objc func getUrl(sender: UITapGestureRecognizer){ guard let url = self.rssUrl else { return } print(url) UIApplication.shared.open(url, options: [:], completionHandler: nil)
uitappostation
,我尝试打印它(它打印URL),但它不想实际打开URL
@objc func getUrl(sender: UITapGestureRecognizer){
guard let url = self.rssUrl else { return }
print(url)
UIApplication.shared.open(url, options: [:], completionHandler: nil)
}
在这里抓取URL
var rssUrl: URL?
var item: RSSItem! {
DispatchQueue.global(qos: .userInteractive).async {
//other code
let store_Article = Article(dict: ["text": sum, "rssUrl": rssLink])
storedArticle.append(store_Article)
let data = dataUrl.init(articleUrl: store_Article).someUrl
DispatchQueue.main.sync {
//other code
}
}
}
编辑
它打印:http://www.instyle.com/news/rihanna-30th-birth-party——文件:///
举个例子试试这个
编辑
@objc func getUrl(sender: UITapGestureRecognizer)
{
guard let url = URL(string: YOUR_URL_STRING) else {
return //be safe
}
if #available(iOS 10.0, *) {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
UIApplication.shared.openURL(url)
}
}
你得到了什么(url)?@KamleshShingarakhiya查看编辑最近几天你有多少帐户?这至少是三个。为什么?@rmaddy just 3它一直禁止我问问题,即使在一个小时之后week@rmaddy我有一个帐户,做得很好,然后突然堆栈禁止我问这不工作,它给出了一个错误类型,URL是类型URL我检查了它的工作良好。请检查编辑应答!快乐编码!!