在SwiftUI中更新树结构的UI
我有一个ObserveObject类,在SwiftUI中更新树结构的UI,swift,tree,swiftui,children,observedobject,Swift,Tree,Swiftui,Children,Observedobject,我有一个ObserveObject类,Model0,它有一个已发布的对象嵌套的。嵌套的对象表示递归树结构。我希望能够更新树结构并适当地更新UI。但是,在下面的代码中,当我更新nested对象的子对象时,UI没有更新,我假设是因为对nested的引用没有更改。当我更改树结构中的任何嵌套对象时,如何使UI更新 class Nested: Identifiable { var id: UUID = UUID() var name: String var children:[Ne
Model0
,它有一个已发布的对象嵌套的。嵌套的对象表示递归树结构。我希望能够更新树结构并适当地更新UI。但是,在下面的代码中,当我更新nested
对象的子对象时,UI没有更新,我假设是因为对nested
的引用没有更改。当我更改树结构中的任何嵌套对象时,如何使UI更新
class Nested: Identifiable {
var id: UUID = UUID()
var name: String
var children:[Nested]
init(name: String, children:[Nested]) {
self.children = children
self.name = name
}
}
class Model0 : ObservableObject {
@Published var nested: Nested
init(nested: Nested) {
self.nested = nested
}
func update() {
nested.children[0] = Nested(name:"New", children: [])
}
}
struct NestedView: View {
var nested: Nested
var body: some View {
VStack {
Text(nested.name)
ForEach(nested.children) { c in
NestedView(nested: c)
}
}
}
}
struct Test: View {
@ObservedObject var model: Model0 = Model0(nested: Nested(name: "Parent" ,children: [Nested(name: "Child", children: [])]))
var body: some View {
VStack {
Button(action: {
self.model.update()
}) {
Text("Update")
}
NestedView(nested: model.nested)
}
}
}
若您决定建立引用类型模型,那个么您需要使它们都是可观察的,这样每个级别都可以更新相应的视图。当然,每个级别模型都有单独的视图
考虑到以上因素,这里有一个解决方案。使用Xcode 12/iOS 14进行测试
仅限修改部分:
class Nested: ObservableObject, Identifiable {
var id: UUID = UUID()
@Published var name: String
@Published var children:[Nested]
init(name: String, children:[Nested]) {
self.children = children
self.name = name
}
}
struct NestedView: View {
@ObservedObject var nested: Nested
var body: some View {
VStack {
Text(nested.name)
ForEach(nested.children) { c in
NestedView(nested: c)
}
}
}
}