Swift 根据数组字符串的顺序对字典数组进行排序

我有一个字典数组，如：

    "account": [{
        "accountNo": "32211",
        "accountType": "01",
    }, {
        "accountNo": "12233",
        "accountType": "01",
    }, {
        "accountNo": "22244",
        "accountType": "01",
    }]

我想通过比较此orderList数组上的accountNo对其进行排序：

["12233","22244"","11111","32211","44444"]

字典的排序数组应如下所示：

    "account": [{
        "accountNo": "12233",
        "accountType": "01",
    }, {
        "accountNo": "22244",
        "accountType": "01",
    }, {
        "accountNo": "32211",
        "accountType": "01",
    }]

---

我该怎么做呢？

如果

字典

let dict = [
    "account": [
        [
            "accountNo": "32211",
            "accountType": "01",
        ], [
            "accountNo": "12233",
            "accountType": "01",
        ], [
            "accountNo": "22244",
            "accountType": "01",
        ]
    ]
]

而
顺序是

let order = ["12233","22244","11111","32211","44444"]

您可以对
帐户
数组
进行排序，如下所示：

if let accounts = dict["account"] as? [[String:Any]] {
    let sortedAccounts = accounts.sorted {
        if let n1 = $0["accountNo"] as? String, let n2 = $1["accountNo"] as? String, let index1 = order.firstIndex(of: n1), let index2 = order.firstIndex(of: n2) {
            return index1 < index2
        }
        return false
    }
    print(sortedAccounts)
}

如果let accounts=dict[“account”]as？[[String:Any]]{
让sortedAccounts=accounts.sorted{
如果让n1=$0[“accountNo”]作为字符串，让n2=$1[“accountNo”]作为字符串，让index1=order.firstIndex（of:n1），让index2=order.firstIndex（of:n2）{
返回index1
您尝试过什么？请分享你的代码。