Swift2 运行随机操作

我知道如何随机运行操作吗

let action2 = SKAction.colorizeWithColor(UIColor.cyanColor(), colorBlendFactor: 1.0, duration: 3)
let action3 = SKAction.colorizeWithColor(UIColor.purpleColor(), colorBlendFactor: 1.0, duration: 3)
let action6 = SKAction.colorizeWithColor(UIColor.darkGrayColor(), colorBlendFactor: 1.0, duration: 3)
let action7 = SKAction.colorizeWithColor(UIColor.yellowColor(), colorBlendFactor: 1.0, duration: 3)
let action8 = SKAction.colorizeWithColor(UIColor.redColor(), colorBlendFactor: 0.3, duration: 3)
let action9 = SKAction.colorizeWithColor(UIColor.orangeColor(), colorBlendFactor: 1.0, duration: 3)

let round1 = (SKAction.repeatActionForever(SKAction.sequence([action2,action3,action6,action7,action8,action9])))
let round2 = (SKAction.repeatActionForever(SKAction.sequence([action9,action8,action6,action7,action3,action2])))
let round3 = (SKAction.repeatActionForever(SKAction.sequence([action3,action9,action6,action3,action2,action7])))


var colors = [round1,round2,round3]

self.scene?.runAction(arc4random_uniform(UInt32(colors.count)))

我在

self.scene？.runAction（arc4random\u uniform（UInt32（colors.count）））上得到了错误。

此代码将生成以下内容：

 self.scene?.runAction(4)
 self.scene?.runAction(2)

有问题吗

你需要一个动作数组，你可以把动作放在某个地方，然后通过索引从中获取

试一试

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谢谢你的帮助！但是获取错误“Type”SKAction没有下标成员

 self.scene?.runAction(4)
 self.scene?.runAction(2)

let arrayOfActions = [action2, action3, action4,..] //complete with the actions

 self.scene?.runAction(arrayOfActions[arc4random_uniform(UInt32(colors.count))])