Swift3 无法使用post将数据保存到json

我无法将数据保存回写在文本字段中的json，当单击save按钮时，必须将更新的数据保存到json。 以下是我编写的关于保存按钮操作的代码：

if let id = UserDefaults.standard.string(forKey: "NgoId"){
        var request = URLRequest(url: URL(string: "http://www.shreetechnosolution.com/funded/ngo_profile.php?ngoid=\(id)")!)
        request.httpMethod = "POST"
        let postString = "Nameofngo=\(textngoname.text!)&NameofChiefFunctionary=\(textcheiffunction.text!)&NameofChairman=\(textchairman.text!)&NameofSeceratary=\(textsecratary.text!)&NameofTreasurer=\(texttreasurer.text!)&ParentOrganization=\(textparentorg.text!)&AboutNGO=\(Textngo.text)&photoofNGO=\(imageviewngo.image)&ngoid=\(id)&value=NGO"
        request.httpBody = postString.data(using: .utf8)
        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data, error == nil else {                                                 // check for fundamental networking error
                print("error=\(error ?? "" as! Error)")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {           // check for http errors
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(String(describing: response))")

        }
            let json = try! JSONSerialization.jsonObject(with: data, options: []) as! NSDictionary
            let msg = json.value(forKey: "message") as! NSString!



            let alert : UIAlertView = UIAlertView(title: "Alert box!", message: "\(msg!).",delegate: nil, cancelButtonTitle: "OK")
            alert.show()
        }
        task.resume()
        }

---

尝试以下方式发布数据代码，这将对您有所帮助。并始终尝试使用捕捉来获取错误。下面是您的工作代码和响应

    UserDefaults.standard.setValue(1, forKey: "NgoId");

    if let id = UserDefaults.standard.string(forKey: "NgoId"){
        var request = URLRequest(url: URL(string: "http://www.shreetechnosolution.com/funded/ngo_profile.php?ngoid=\(id)")!)
        request.httpMethod = "POST"

        var postJson = Dictionary<String, Any>.init();
        postJson["Nameofngo"] = "NONAME";
        postJson["NameofChiefFunctionary"] = "";
        postJson["NameofChairman"] = "";
        postJson["NameofSeceratary"] = "";
        postJson["NameofTreasurer"] = "";
        postJson["ParentOrganization"] = "";
        postJson["AboutNGO"] = "";
        postJson["ngoid"] = id;
        postJson["value"] = "NGO";

        print("post json \(postJson)");

        do {
           let postData = try JSONSerialization.data(withJSONObject: postJson, options: JSONSerialization.WritingOptions.prettyPrinted);
            request.httpBody = postData;
        }catch let err {
            print("exception is \(err)");
        }

        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let responseData = data, error == nil else {                                                 // check for fundamental networking error
                print("error=\(error ?? "" as! Error)")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {           // check for http errors
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(String(describing: response))")
            }

            let json = try! JSONSerialization.jsonObject(with: responseData, options: []) as! NSDictionary

            print("json response \(json)");
        }
        task.resume()
    }

---

尝试以下方式发布数据代码，这将对您有所帮助。并始终尝试使用捕捉来获取错误。下面是您的工作代码和响应

    UserDefaults.standard.setValue(1, forKey: "NgoId");

    if let id = UserDefaults.standard.string(forKey: "NgoId"){
        var request = URLRequest(url: URL(string: "http://www.shreetechnosolution.com/funded/ngo_profile.php?ngoid=\(id)")!)
        request.httpMethod = "POST"

        var postJson = Dictionary<String, Any>.init();
        postJson["Nameofngo"] = "NONAME";
        postJson["NameofChiefFunctionary"] = "";
        postJson["NameofChairman"] = "";
        postJson["NameofSeceratary"] = "";
        postJson["NameofTreasurer"] = "";
        postJson["ParentOrganization"] = "";
        postJson["AboutNGO"] = "";
        postJson["ngoid"] = id;
        postJson["value"] = "NGO";

        print("post json \(postJson)");

        do {
           let postData = try JSONSerialization.data(withJSONObject: postJson, options: JSONSerialization.WritingOptions.prettyPrinted);
            request.httpBody = postData;
        }catch let err {
            print("exception is \(err)");
        }

        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let responseData = data, error == nil else {                                                 // check for fundamental networking error
                print("error=\(error ?? "" as! Error)")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {           // check for http errors
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(String(describing: response))")
            }

            let json = try! JSONSerialization.jsonObject(with: responseData, options: []) as! NSDictionary

            print("json response \(json)");
        }
        task.resume()
    }

---

你能告诉我你的httpStatus代码是什么吗。并给我一个示例NgoId密钥进行测试。你能告诉我你的httpStatus代码是什么吗。并给我一个示例NgoId密钥进行测试。事实上，我没有在这里设置值，我希望在登录我的应用程序时使用该id，我已经将其存储在id变量中，并且您在poststring“”中检查为null的文本字段具有值，以防发生什么情况，然后可以使用您的id变量，我还通过使用以下行使用您的id变量，UserDefaults.standard.setValue（1，forKey：“NgoId”）；实际上，我没有在这里设置值，我想在我登录我的应用程序时使用该id，我已经将其存储在id变量中，并且您在poststring“”中检查为null的文本字段中有值，以防发生什么情况。使用您的id变量，我也使用您的id变量，使用以下行，UserDefaults.standard.setValue（1，forKey：“NgoId”）；

    if let successVal = response?["success"] as? NSNumber {
        uWillGetValueHere = successVal;
    }