将所有记录插入Symfony中的连接表
我有一个下一个表格:测验、问题和问题测验。我有一种多对多的关系。 插入工作适用于表格测验和问题,但在表格问题中,测验只插入了一条记录 我的桌子 “问题”,没关系将所有记录插入Symfony中的连接表,symfony,doctrine-orm,insert,many-to-many,junction-table,Symfony,Doctrine Orm,Insert,Many To Many,Junction Table,我有一个下一个表格:测验、问题和问题测验。我有一种多对多的关系。 插入工作适用于表格测验和问题,但在表格问题中,测验只插入了一条记录 我的桌子 “问题”,没关系 +----+--------+ | id | title | +----+--------+ | 61 | Title1 | | 62 | Title2 | | 63 | Title3 | +----+--------+ +----+-------+--------+ | id | name | status | +----+--
+----+--------+
| id | title |
+----+--------+
| 61 | Title1 |
| 62 | Title2 |
| 63 | Title3 |
+----+--------+
+----+-------+--------+
| id | name | status |
+----+-------+--------+
| 27 | Name1 | 0 |
+----+-------+--------+
“测验”,没关系
+----+--------+
| id | title |
+----+--------+
| 61 | Title1 |
| 62 | Title2 |
| 63 | Title3 |
+----+--------+
+----+-------+--------+
| id | name | status |
+----+-------+--------+
| 27 | Name1 | 0 |
+----+-------+--------+
“问答游戏”
最后一个表中必须插入61,62,63 quiestion_id,但只插入一条记录
我的控制器的碎片
$quiz = new Quiz();
$question = new Question();
$form = $this->get('form.factory')->createNamed('quiz', QuizType::class, $quiz);
$quiz->getQuestions()->add($question);
$question->addQuiz($quiz);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($quiz);
$em->persist($question);
$em->flush();
}
$quiz = new Quiz();
$question = new Question();
//...
$question->addQuiz($quiz);
问题实体的调用证据
$quiz->getQuestions()->add($question);
$question->addQuiz($quiz);
我使用集合类型,可以插入任意数量的问题
更新QuizType表单。
class QuizType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('name', TextType::class, array('attr' => ['class' => 'form-control name-quiz'], 'label' => 'Name Quiz'))
->add('status', CheckboxType::class, array(
'label' => 'Status Quiz',
'required' => false))
->add('save', SubmitType::class, ['label' => 'Add', 'attr' => ['class' => 'btn btn-primary']]);
$builder
->add('questions', CollectionType::class, array(
'entry_type' => QuestionType::class,
'entry_options' => array('label' => false),
'allow_add' => true,
));
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => Quiz::class
]);
}
}
如果我调试方法addQuestion()
,我会在带有参数[null]的疑问(标题)值(?)中插入错误。但如果我做了一个测试
Question {#583 ▼
-id: null
-title: "123"
-quiz: ArrayCollection {#584 ▼
-elements: array:1 [▼
0 => Quiz {#581 ▼
-id: null
-name: "123"
-questions: ArrayCollection {#580 ▶}
-status: false
}
]
}
-answers: ArrayCollection {#585 ▶}
}
调试$form->get('questions')->getData()返回
没有
测验
和问题
实体-很难判断。但是
我想问题出在你的控制器上
$quiz = new Quiz();
$question = new Question();
$form = $this->get('form.factory')->createNamed('quiz', QuizType::class, $quiz);
$quiz->getQuestions()->add($question);
$question->addQuiz($quiz);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($quiz);
$em->persist($question);
$em->flush();
}
$quiz = new Quiz();
$question = new Question();
//...
$question->addQuiz($quiz);
所以你创建了一个新的测验,应该有多个问题,对吗?
但是你只回答一次问题
$question->addQuiz($quiz);
所以正确的方法应该是(有点冗长,这样你就能明白重点)
看看这个例子(),了解许多关系,特别是addUSerGroup()
和addUser()
方法
在控制器(无表单)中尝试建议的方法,看看它是否有效,以及您是否在question\u quick
表中获得了多行内容
更新:
我认为您正在寻找的“魔力”是测验实体中的cascade={“persist”}
。看看这篇文章()。尽管视频不是免费的,但是文本是可以的
1) 在您的实体中设置cascade
2) 更新了测验类中的youaddQuestion()
方法,如下所示
public function addQuestion(Question $question)
{
// do not add same questions more than once.
if ($this->questions->contains($question)) {
return;
}
$this->questions[] = $question; // to add new question to that quiz
$question->addQuiz($this); // this quiz now also belongs to a question
}
3) 获取嵌入集合以使用prototype
=>。因此,您可以随时添加新问题
4) 提交后,只需拨打:
if ($form->isSubmitted() && $form->isValid()) {
$quiz = $form->getData();
$em->persist($quiz);
$em->flush();
}
4.1)如果不起作用,请尝试在提交的问题集合上循环
if ($form->isSubmitted() && $form->isValid()) {
$quiz = $form->getData();
// since getQuestions() gives you an ArrayCollection, isEmpty is a built in method
if(!$quiz->getQuestions()->isEmpty())
{
// this is kinda bad, but you'll have to debug and play around
foreach ($quiz->getQuestions() as $new_question)
{
$em->persist($new_question);
}
}
$em->persist($quiz);
$em->flush();
}
我解决了我的问题。我发布我的代码,也许它会帮助别人 我的实体
问题
class Question
{
/**
* @ORM\Id()
* @ORM\GeneratedValue()
* @ORM\Column(type="integer")
*/
private $id;
/**
* @ORM\Column(type="text")
*/
private $title;
/**
* @ORM\ManyToMany(targetEntity="App\Entity\Quiz", inversedBy="questions")
*/
private $quiz;
public function __construct()
{
$this->quiz = new ArrayCollection();
}
public function getId(): ?int
{
return $this->id;
}
public function getTitle(): ?string
{
return $this->title;
}
public function setTitle(string $title): self
{
$this->title = $title;
return $this;
}
/**
* @return Collection|Quiz[]
*/
public function getQuiz(): Collection
{
return $this->quiz;
}
public function addQuiz(Quiz $quiz): self
{
if (!$this->quiz->contains($quiz)) {
$this->quiz[] = $quiz;
}
return $this;
}
public function removeQuiz(Quiz $quiz): self
{
if ($this->quiz->contains($quiz)) {
$this->quiz->removeElement($quiz);
}
return $this;
}
}
我的实体测验
class Quiz
{
/**
* @ORM\Id()
* @ORM\GeneratedValue()
* @ORM\Column(type="integer")
*/
private $id;
/**
* @ORM\Column(type="string", length=191)
*/
private $name;
/**
* @ORM\ManyToMany(targetEntity="App\Entity\Question", mappedBy="quiz", cascade={"persist"})
*/
private $questions;
/**
* @ORM\Column(type="boolean")
*/
private $status;
public function __construct()
{
$this->questions = new ArrayCollection();
}
public function getId(): ?int
{
return $this->id;
}
/**
* @return string|null
*/
public function getName(): ?string
{
return $this->name;
}
public function setName(string $name): self
{
$this->name = $name;
return $this;
}
/**
* @return Collection|Question[]
*/
public function getQuestions(): Collection
{
return $this->questions;
}
public function addQuestion(Question $question): self
{
if (!$this->questions->contains($question)) {
$this->questions[] = $question;
$question->addQuiz($this);
}
return $this;
}
public function removeQuestion(Question $question): self
{
if ($this->questions->contains($question)) {
$this->questions->removeElement($question);
$question->removeQuiz($this);
}
return $this;
}
public function getStatus(): ?bool
{
return $this->status;
}
public function setStatus(bool $status): self
{
$this->status = $status;
return $this;
}
}
问题类型
表格
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('title', TextareaType::class, array('attr' => array('class' => 'form-control'), 'label' => false));
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => Question::class
]);
}
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('name', TextType::class, array('attr' => ['class' => 'form-control name-quiz'], 'label' => 'Name quiz'))
->add('status', CheckboxType::class, array(
'label' => 'Status quiz',
'required' => false))
->add('save', SubmitType::class, ['label' => 'Add', 'attr' => ['class' => 'btn btn-primary']]);
$builder
->add('questions', CollectionType::class, array(
'entry_type' => QuestionType::class,
'entry_options' => array('label' => false),
'allow_add' => true,
'by_reference' => false,
));
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => Quiz::class
]);
}
QuizType
表单
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('title', TextareaType::class, array('attr' => array('class' => 'form-control'), 'label' => false));
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => Question::class
]);
}
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('name', TextType::class, array('attr' => ['class' => 'form-control name-quiz'], 'label' => 'Name quiz'))
->add('status', CheckboxType::class, array(
'label' => 'Status quiz',
'required' => false))
->add('save', SubmitType::class, ['label' => 'Add', 'attr' => ['class' => 'btn btn-primary']]);
$builder
->add('questions', CollectionType::class, array(
'entry_type' => QuestionType::class,
'entry_options' => array('label' => false),
'allow_add' => true,
'by_reference' => false,
));
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => Quiz::class
]);
}
最后是我的控制器
$quiz = new Quiz();
$form = $this->get('form.factory')->createNamed('quiz', QuizType::class, $quiz);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($quiz);
$em->flush();
return $this->redirectToRoute('admin');
}
很好,是的:)谢谢大家。请出示您的
测验类型?似乎从提交的数据到您的测验
实体的映射没有像您预期的那样工作。@xabbuhI我已更新。哦,您是否也可以显示您的测验
和问题
实体?@xabbuh请看这里。我想知道$this->questions[]=$question是否调用过code>,如果真的有效$this->questions
在您的测验中
实体是一个条令集合。所以我希望这一行是$this->questions->add($question)代码>。这对我不起作用,因为我想插入任意数量的问题。在你的例子中,我只能添加3个问题。我已经看到链接了。我尝试了联接表和联接列,但对我无效。这是不正确的。通过这种方法,您可以在测验中添加任意数量的问题。为了演示,我创建了三个问题,并将每个问题添加到一个测验中。如果您将cascade={“persist”}
添加到测验的许多注释中,您将获得自动持久化,因此您不需要手动调用$em->persist($quesion\u X)