可捕获致命错误:参数1传递给?Symfony2

可捕获致命错误:参数1传递给?Symfony2,symfony,Symfony,我被下面的错误消息困住了,很沮丧: 可捕获的致命错误:参数1传递给Medicine\UserBundle\Entity\User ::setUsertype()必须是Medicine\UserBundle\Entity\Usertype的实例, 给定的条令\Common\Collections\ArrayCollection实例,在中调用 /opt/lampp/htdocs/drugs/vendor/symfony/src/symfony/Component/Form/Util /第347行的P

我被下面的错误消息困住了,很沮丧:

可捕获的致命错误:参数1传递给Medicine\UserBundle\Entity\User ::setUsertype()必须是Medicine\UserBundle\Entity\Usertype的实例, 给定的条令\Common\Collections\ArrayCollection实例,在中调用 /opt/lampp/htdocs/drugs/vendor/symfony/src/symfony/Component/Form/Util /第347行的PropertyPath.php,并在/opt/lampp/htdocs/drugs/src中定义/ Medicine/UserBundle/Entity/User.php第224行

我认为这个错误是由于在我的实体中使用了多个域,我甚至尝试在另一个实体中保留一个域

我有一个user实体和一个usertype实体,usertype_id是user表中的一个manytone字段。以下是这两个实体的代码:-

用户

namespace Medicine\UserBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
* @ORM\Entity(repositoryClass="Medicine\UserBundle\Repository\UserRepository")
* @ORM\Table(name="user")
* @ORM\HasLifecycleCallbacks()
*/

class User
{
/**
 * @ORM\Id
 * @ORM\Column(type="integer")
 * @ORM\GeneratedValue(strategy="AUTO")
 * @ORM\HasLifecycleCallbacks()
 */
protected $id;

/**
 * @ORM\Column(type="string")
 */
 protected $username;

 /**
 * @ORM\ManyToOne(targetEntity="Usertype", inversedBy="users")
 * @ORM\JoinColumn(name="usertype_id", referencedColumnName="id")
 */
 protected $usertype;

/**
 * @ORM\Column(type="string")
 */
 protected $image;

/**
 * Set usertype
 *
 * @param Medicine\UserBundle\Entity\Usertype $usertype
 */
public function setUsertype(\Medicine\UserBundle\Entity\Usertype $usertype)
{
    $this->usertype = $usertype;
}

/**
 * Get usertype
 *
 * @return Medicine\UserBundle\Entity\Usertype 
 */
public function getUsertype()
{
    return $this->usertype;
}
}
我只是展示相关的代码,我有上面代码的所有getter和setter方法

用户类型

namespace Medicine\UserBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
* @ORM\Entity(repositoryClass="Medicine\UserBundle\Repository\UsertypeRepository")
* @ORM\Table(name="usertype")
* @ORM\HasLifecycleCallbacks()
*/

class Usertype
{
/**
 * @ORM\Id
 * @ORM\Column(type="integer")
 * @ORM\GeneratedValue(strategy="AUTO")
 * @ORM\HasLifecycleCallbacks()
 */
protected $id;

/**
 * @ORM\Column(type="string")
 */
protected $name;

/**
* @ORM\OneToMany(targetEntity="User", mappedBy="usertype")
*/
protected $users;

public function __construct()
{
    $this->users = new \Doctrine\Common\Collections\ArrayCollection();
}

/**
 * Add users
 *
 * @param Medicine\UserBundle\Entity\User $users
*/
public function addUser(\Medicine\UserBundle\Entity\User $users)
{
    $this->users[] = $users;
}

/**
 * Get users
 *
 * @return Doctrine\Common\Collections\Collection 
 */
public function getUsers()
{
    return $this->users;
}
}
控制器

namespace Medicine\UserBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
* @ORM\Entity(repositoryClass="Medicine\UserBundle\Repository\UserRepository")
* @ORM\Table(name="user")
* @ORM\HasLifecycleCallbacks()
*/

class User
{
/**
 * @ORM\Id
 * @ORM\Column(type="integer")
 * @ORM\GeneratedValue(strategy="AUTO")
 * @ORM\HasLifecycleCallbacks()
 */
protected $id;

/**
 * @ORM\Column(type="string")
 */
 protected $username;

 /**
 * @ORM\ManyToOne(targetEntity="Usertype", inversedBy="users")
 * @ORM\JoinColumn(name="usertype_id", referencedColumnName="id")
 */
 protected $usertype;

/**
 * @ORM\Column(type="string")
 */
 protected $image;

/**
 * Set usertype
 *
 * @param Medicine\UserBundle\Entity\Usertype $usertype
 */
public function setUsertype(\Medicine\UserBundle\Entity\Usertype $usertype)
{
    $this->usertype = $usertype;
}

/**
 * Get usertype
 *
 * @return Medicine\UserBundle\Entity\Usertype 
 */
public function getUsertype()
{
    return $this->usertype;
}
}
当用户想要登录时执行此操作。他将填写用户名密码和用户类型:

public function indexAction()
{
$entity = new User();
    $form = $this->createForm(new LoginForm(), $entity);
    $request = $this->getRequest();
    if ($request->getMethod() == 'POST') {
        $form->bindRequest($request);
        if ($form->isValid()) {
        echo "<pre>"; print_r($entity->getUsertype()); exit;
        $em = $this->getDoctrine()
              ->getEntityManager();
        $em->persist($entity);
        $userrepository = $em->getRepository('MedicineUserBundle:User');
        echo "<pre>"; print_r($entity->getUsertype()); exit;
        $all = $userrepository->findOneBy(array('login' => $entity->getLogin(), 'password' => $entity->getPassword()));
        if($all)
        {
            return $this->redirect($this->generateUrl('MedicineUserBundle_login'));
        }
        }
     }

     return $this->render('MedicineUserBundle:User:loginpage.html.twig',array(
        'form' => $form->createView()
    ));
}

'multiple'=>true
与实体关联定义一起导致此问题

您应该发现,如果您将multiple更改为false(因此只能为您的用户选择一个用户类型),则一切正常

如果您希望一个用户有多个用户类型,那么您有多对多关联—一个用户可以有多个用户类型,而一个用户类型可以有多个用户。请参阅条令的多个关联类型以实现此


希望这能有所帮助。

我认为问题出在您的登录表单中-我们可以看看吗?@jstephenson:-我也用登录表单更新了我的问题