Symfony1 使用spreep将SQL转换为标准

我有一个sql：

SELECT link.ID, link.URL, link.ANCHOR, link.HOME, link.CREATED_AT 
FROM `link`, `linkcategory`
WHERE link.ID=linkcategory.LINK_ID
GROUP BY linkcategory.LINK_ID 
HAVING count(linkcategory.category_id) =(select count(*) from categoria)

我正在尝试生成标准，这是不起作用的标准：

$c = new Criteria();
$c->addJoin(self::ID, LinkcategoryPeer::LINK_ID);
$c->addAsColumn('catCount','(SELECT COUNT(*) FROM CATEGORIA)');
$c->addGroupByColumn(LinkcategoryPeer::LINK_ID);
$having = $c->getNewCriterion(count(LinkcategoryPeer::CATEGORY_ID),$c->getColumnForAs('catCount'));
$c->addHaving($having); 
return self::doSelect($c);

此条件的返回sql如下所示：

SELECT (SELECT COUNT(*) FROM CATEGORIA) AS catCount 
FROM `link`, `linkcategory` 
WHERE link.ID=linkcategory.LINK_ID 
GROUP BY linkcategory.LINK_ID 
HAVING 1='(SELECT COUNT(*) FROM CATEGORIA)'

---

我真的不知道为什么标准不能正确地转换sql。有人知道错误在哪里吗？

试试这个查询。我不记得如何使用推进执行

链接。*

。但是我认为拥有的问题在于，您使用的是PHP count函数而不是MySQL函数

$c = new Criteria();
$c->addSelectColumn(self::ID);
$c->addSelectColumn(self::URL);
$c->addSelectColumn(self::ANCHOR);
$c->addSelectColumn(self::HOME);
$c->addSelectColumn(self::CREATED_AT );

$c->addJoin(self::ID, LinkcategoryPeer::LINK_ID);
$c->addGroupByColumn(LinkcategoryPeer::LINK_ID);

$having = $c->getNewCriterion(
  'COUNT('.LinkcategoryPeer::CATEGORY_ID.')'),
  $c->getColumnForAs('catCount')
);
$c->addHaving($having);

return self::doSelect($c);