Terraform创建多个IP';来自CIDR区块的s
我有变量Terraform创建多个IP';来自CIDR区块的s,terraform,Terraform,我有变量cidr=10.11.12.0/16 和资源计数 resource "aws_network_interface" "first" { count = "${length(var.instance_names)}" provider = "aws.base" subnet_id = "${var.cidr}" private_ips = ["${concat( list(var.first_network_interface_private_ip
cidr=10.11.12.0/16
和资源计数
resource "aws_network_interface" "first" {
count = "${length(var.instance_names)}"
provider = "aws.base"
subnet_id = "${var.cidr}"
private_ips = ["${concat(
list(var.first_network_interface_private_ip),
var.first_network_interface_private_ip_additional
)}"]
source_dest_check = "${var.first_network_interface_source_dest_check_enabled}"
security_groups = [
"${concat(
list(aws_security_group.this.id),
var.first_network_interface_security_group_additional
)}"
]
depends_on = [
"aws_security_group.this",
]
tags = "${merge(
var.tags_global,
var.tags_module,
map("Name", format("%s - First Interface", element(var.instance_names, count.index))),
map("Description", format("%s", element(var.instance_names, count.index)))
)}"
}
我希望每次迭代都能得到不同的IP
我遇到了,不知道如何从中提取前三个八位组
10.11.12,可能需要使用正则表达式从CIDR?获取八位字节,或者有其他解决方案解决我的问题?解决了它
private_ips = ["${concat(
list(cidrhost(var.cidr , count.index + 249)),
var.first_network_interface_private_ip_additional
)}"]
为两台机器获得10.11.12.249/250 IP解决了这个问题
private_ips = ["${concat(
list(cidrhost(var.cidr , count.index + 249)),
var.first_network_interface_private_ip_additional
)}"]
为两台机器获得10.11.12.249/250 IP