Text 如何剥离所有引号并使用记事本重新添加文本选项卡分隔的文件++；

我需要在SQL Server中导入一些相当脏的文本选项卡数据。它失败是因为其中一个列分隔符出现了问题。这是因为某些列中出现了双引号。我正在努力纠正这一点，我的理论是删除所有引号，然后用正则表达式将每个制表符分隔的字段再次用单引号括起来。尽管搜索了很多类似的帖子，我还是找不到一个有效的答案，有人能帮忙吗

它不一定是记事本+，但它是我最熟悉的

    "REDACTED"  "REDACTED"  REDACTED    "REDACTED"  "REDACTED"  "REDACTED"  ""  "REDACTED"    "REDACTED"    "REDACTED"  ""Problematic, field""  ""  ""  ""  "REDACTED"  "REDACTED"  "REDACTED"  ".00"   "805400838" 94.17   22.77   4.13    ".83"   117.95  220 2   0   "REDACTED"

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如果您的要求没有进一步解释，我想您应该删除所有双引号，并在每个字段周围添加单引号

这就是工作：

• Ctrl+H
• 查找内容：

  （？
  替换为：
  （？1'$1'：'$3'）
  检查环绕
  检查正则表达式
  全部替换
  

说明：

  (?<=\s)           # positive lookbehind, make sure we have a space before
  ""                # 2 double quote
  (?=\s|$)          # positive lookahead, make sure we have aspace after or end of line
|               # OR
  (?<=\s)           # positive lookbehind, make sure we have a space before
  ([^"\s]+)         # group 1, 1 or more any characte that is not space or double quote
|               # OR
  (?<!")            # negative lookbehind, make sure we haven't a double quote before
  ("+)              # group 2, 1 or more double quote
  ([^"]+)           # group 3, 1 or more non double quote
  \2                # reference to group 2, same number of double quote

(?1             # conditional replacement, if group 1 exists
  '$1'              # content of group 1 surrounded with single quotes
 :              # else
  '$3'              # content of group 3 surrounded with single quotes
)               # end condition

屏幕截图（之前）：

  (?<=\s)           # positive lookbehind, make sure we have a space before
  ""                # 2 double quote
  (?=\s|$)          # positive lookahead, make sure we have aspace after or end of line
|               # OR
  (?<=\s)           # positive lookbehind, make sure we have a space before
  ([^"\s]+)         # group 1, 1 or more any characte that is not space or double quote
|               # OR
  (?<!")            # negative lookbehind, make sure we haven't a double quote before
  ("+)              # group 2, 1 or more double quote
  ([^"]+)           # group 3, 1 or more non double quote
  \2                # reference to group 2, same number of double quote

(?1             # conditional replacement, if group 1 exists
  '$1'              # content of group 1 surrounded with single quotes
 :              # else
  '$3'              # content of group 3 surrounded with single quotes
)               # end condition

屏幕截图（之后）：

  (?<=\s)           # positive lookbehind, make sure we have a space before
  ""                # 2 double quote
  (?=\s|$)          # positive lookahead, make sure we have aspace after or end of line
|               # OR
  (?<=\s)           # positive lookbehind, make sure we have a space before
  ([^"\s]+)         # group 1, 1 or more any characte that is not space or double quote
|               # OR
  (?<!")            # negative lookbehind, make sure we haven't a double quote before
  ("+)              # group 2, 1 or more double quote
  ([^"]+)           # group 3, 1 or more non double quote
  \2                # reference to group 2, same number of double quote

(?1             # conditional replacement, if group 1 exists
  '$1'              # content of group 1 surrounded with single quotes
 :              # else
  '$3'              # content of group 3 surrounded with single quotes
)               # end condition

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预期结果是什么？每个字符串都必须用单引号括起来，即使它是空的。我编辑了我的帖子，因此在示例中，您可以看到字段周围出现了双引号，这可能是由于供应商使用了“作为一种转义。如果一个值或日期最后用引号括起来，这并不是世界末日，因为我可以修复导入后的问题。那么，您想用单引号替换所有双引号，那么空格或不带引号的单词呢？我不清楚，请简化一下示例并添加预期结果。