UltraTree基础设施-选择所有节点
在Infragistics UltraTree中,如何选择根下的所有节点?据我所知,没有选择所有节点的方法。但你可以像这样建造自己的:UltraTree基础设施-选择所有节点,tree,infragistics,tree-nodes,ultratree,Tree,Infragistics,Tree Nodes,Ultratree,在Infragistics UltraTree中,如何选择根下的所有节点?据我所知,没有选择所有节点的方法。但你可以像这样建造自己的: Queue<UltraTreeNode> queue = new Queue<UltraTreeNode>(ultraTree1.Nodes); while (queue.Count > 0) { UltraTreeNode node = queue.Dequeue(); foreach(UltraTreeNode
Queue<UltraTreeNode> queue = new Queue<UltraTreeNode>(ultraTree1.Nodes);
while (queue.Count > 0)
{
UltraTreeNode node = queue.Dequeue();
foreach(UltraTreeNode child in node.Nodes)
queue.Enqueue(child);
node.Selected = true;
}
Queue Queue=新队列(ultraTree1.Nodes);
而(queue.Count>0)
{
UltraTreeNode节点=queue.Dequeue();
foreach(node.Nodes中的UltraTreeNode子节点)
排队。排队(子级);
node.Selected=true;
}
对此的一个可能修改是使用yield return语句将所有树节点作为可枚举集合提供:
private IEnumerable<UltraTreeNode> AllTreeNodes()
{
Queue<UltraTreeNode> queue = new Queue<UltraTreeNode>(ultraTree1.Nodes.OfType<UltraTreeNode>());
while (queue.Count > 0)
{
UltraTreeNode node = queue.Dequeue();
foreach (UltraTreeNode child in node.Nodes)
queue.Enqueue(child);
yield return node;
}
}
foreach (var node in AllTreeNodes())
{
// Take whatever action is needed
//
node.Selected = true;
}