Tsql SQL DateDiff，无周末和公共假日
我正在寻找解决方案，如何选择两个日期之间的天数没有周末和公共假期 到目前为止，我有：Tsql SQL DateDiff，无周末和公共假日,tsql,date-range,date-difference,Tsql,Date Range,Date Difference,我正在寻找解决方案，如何选择两个日期之间的天数没有周末和公共假期 到目前为止，我有： SELECT evnt.event_id, evnt.date_from, evnt.date_to, DATEDIFF(DD, evnt.date_from, evnt.date_to) - (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2) - CASE WHEN DATEPART(DW,
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
FROM events AS evnt
- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
-(SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
FROM events AS evnt
看起来您在
COUNT（*）之前缺少SELECT
语句
试试这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
FROM events AS evnt
取消注释应该是一个子查询
--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
像这样：
- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
（我知道这已经得到了回答，但无论如何我都会把它扔掉…）
与单独的公共假日表相比，将每天作为一行的日历表可能不是一个坏主意。请参阅本文中的演示和可下载的T-SQL代码。包括两篇关于查询和会计年度的后续文章 我看到了如下示例
如果您正在寻找“工作日差异”，请将其与正常日历日差异（即DATEDIFF）进行比较。在这两种情况下，两个相邻工作日之间的差值应为1天。其他解决方案在星期二和星期三之间的两个工作日内完成
DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '1/17/19'
SET @EndDate = '1/18/19'
-- CalendarDateDiff vs Business Date Diff
SELECT
DATEDIFF(d, @StartDate, @EndDate) AS CalendarDateDiff
, (DATEDIFF(dd, @StartDate, @EndDate) + 1)
-1
-(DATEDIFF(wk, @StartDate, @EndDate) * 2)
-(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END) AS CalendarDays
三个标量函数：ShiftHolidayToWorkday、GetHoliday和GetWorkDays
create FUNCTION [dbo].[ShiftHolidayToWorkday](@date date)
RETURNS date
AS
BEGIN
IF DATENAME( dw, @Date ) = 'Saturday'
SET @Date = DATEADD(day, - 1, @Date)
ELSE IF DATENAME( dw, @Date ) = 'Sunday'
SET @Date = DATEADD(day, 1, @Date)
RETURN @date
END
GO
create FUNCTION [dbo].[GetHoliday](@date date)
RETURNS varchar(50)
AS
BEGIN
declare @s varchar(50)
SELECT @s = CASE
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]+1) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-07-04') = @date THEN 'Independence Day'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-12-25') = @date THEN 'Christmas Day'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-12-31') = @date THEN 'New Years Eve'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-11-11') = @date THEN 'Veteran''s Day'
WHEN [Month] = 1 AND [DayOfMonth] BETWEEN 15 AND 21 AND [DayName] = 'Monday' THEN 'Martin Luther King Day'
WHEN [Month] = 5 AND [DayOfMonth] >= 25 AND [DayName] = 'Monday' THEN 'Memorial Day'
WHEN [Month] = 9 AND [DayOfMonth] <= 7 AND [DayName] = 'Monday' THEN 'Labor Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 23 AND 29 AND [DayName] = 'Friday' THEN 'Day After Thanksgiving'
ELSE NULL END
FROM (
SELECT
[Year] = YEAR(@date),
[Month] = MONTH(@date),
[DayOfMonth] = DAY(@date),
[DayName] = DATENAME(weekday,@date)
) c
RETURN @s
END
GO
create FUNCTION [dbo].GetHolidays(@year int)
RETURNS TABLE
AS
RETURN (
select dt, dbo.GetHoliday(dt) as Holiday
from (
select dateadd(day, number, convert(varchar,@year) + '-01-01') dt
from master..spt_values
where type='p'
) d
where year(dt) = @year and dbo.GetHoliday(dt) is not null
)
create proc UpdateHolidaysTable
as
if not exists(select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'Holidays')
create table Holidays(dt date primary key clustered, Holiday varchar(50))
declare @year int
set @year = 1990
while @year < year(GetDate()) + 20
begin
insert into Holidays(dt, Holiday)
select a.dt, a.Holiday
from dbo.GetHolidays(@year) a
left join Holidays b on b.dt = a.dt
where b.dt is null
set @year = @year + 1
end
create FUNCTION [dbo].[GetWorkDays](@StartDate DATE = NULL, @EndDate DATE = NULL)
RETURNS INT
AS
BEGIN
IF @StartDate IS NULL OR @EndDate IS NULL
RETURN 0
IF @StartDate >= @EndDate
RETURN 0
DECLARE @Days int
SET @Days = 0
IF year(@StartDate) * 100 + datepart(week, @StartDate) = year(@EndDate) * 100 + datepart(week, @EndDate)
--same week
select @Days = (DATEDIFF(dd, @StartDate, @EndDate))
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
ELSE
--diff weeks
select @Days = (DATEDIFF(dd, @StartDate, @EndDate) + 1)
- (DATEDIFF(wk, @StartDate, @EndDate) * 2)
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
RETURN @Days
END
创建函数[dbo]。[ShiftHolidayToWorkday]（@date）
返回日期
作为
开始
如果DATENAME（dw，@Date）=“星期六”
设置@Date=DATEADD（天，-1，@Date）
如果DATENAME（dw，@Date）=“星期日”
设置@Date=DATEADD（第1天，@Date）
返回@日期
结束
去
创建函数[dbo].[GetHoliday]（@date-date）
返回varchar（50）
作为
开始
声明@s varchar（50）
选择@s=CASE
当dbo.ShiftHolidayToWorkday（转换（varchar，[Year]）+'-01-01'）=@日期，然后是“新年”
当dbo.ShiftHolidayToWorkday（CONVERT（varchar，[Year]+1）+'-01-01'）=@date然后是'New Year'
当dbo.ShiftHolidayToWorkday（转换（varchar，[Year]）+'-07-04'）=@日期，然后是“独立日”
当dbo.ShiftHolidayToWorkday（转换（varchar，[Year]）+'-12-25'）=@日期，然后转换为“圣诞节”
--当dbo.ShiftHolidayToWorkday（转换（varchar，[Year]）+'-12-31'）=@日期，然后是“新年前夜”
--当dbo.ShiftHolidayToWorkday（转换为（varchar，[Year]）+'-11-11'）=@日期，然后是“退伍军人日”
当[Month]=1且[DayOfMonth]介于15和21之间且[DayName]=周一时，则为“马丁·路德·金日”
当[月]=5且[月日]>=25且[日名]=“星期一”时，则为“阵亡将士纪念日”
当[Month]=9且[DayOfMonth]=EndDate时
返回0
声明@Days int
设置@Days=0
如果年（@StartDate）*100+日期部分（周，@StartDate）=年（@EndDate）*100+日期部分（周，@EndDate）
--同一周
选择@Days=（DATEDIFF（dd、@StartDate、@EndDate））
-（DATENAME（dw，@StartDate）=“Sunday”时的大小写为1，否则为0结束）
-（DATENAME（dw，@EndDate）=“Saturday”时的大小写，然后为1，否则为0结束）
-（从假期中选择计数（*），其中dt介于@StartDate和@EndDate之间）
其他的
--不同周
选择@Days=（DATEDIFF（dd、@StartDate、@EndDate）+1）
-（日期差异（周、开始日期、结束日期）*2）
-（DATENAME（dw，@StartDate）=“Sunday”时的大小写为1，否则为0结束）
-（DATENAME（dw，@EndDate）=“Saturday”时的大小写，然后为1，否则为0结束）
-（从假期中选择计数（*），其中dt介于@StartDate和@EndDate之间）
返回@天
结束
Good solution可能重复，但如果同一天有多个公共假日，您将休假
create FUNCTION [dbo].[ShiftHolidayToWorkday](@date date)
RETURNS date
AS
BEGIN
IF DATENAME( dw, @Date ) = 'Saturday'
SET @Date = DATEADD(day, - 1, @Date)
ELSE IF DATENAME( dw, @Date ) = 'Sunday'
SET @Date = DATEADD(day, 1, @Date)
RETURN @date
END
GO
create FUNCTION [dbo].[GetHoliday](@date date)
RETURNS varchar(50)
AS
BEGIN
declare @s varchar(50)
SELECT @s = CASE
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]+1) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-07-04') = @date THEN 'Independence Day'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-12-25') = @date THEN 'Christmas Day'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-12-31') = @date THEN 'New Years Eve'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-11-11') = @date THEN 'Veteran''s Day'
WHEN [Month] = 1 AND [DayOfMonth] BETWEEN 15 AND 21 AND [DayName] = 'Monday' THEN 'Martin Luther King Day'
WHEN [Month] = 5 AND [DayOfMonth] >= 25 AND [DayName] = 'Monday' THEN 'Memorial Day'
WHEN [Month] = 9 AND [DayOfMonth] <= 7 AND [DayName] = 'Monday' THEN 'Labor Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 23 AND 29 AND [DayName] = 'Friday' THEN 'Day After Thanksgiving'
ELSE NULL END
FROM (
SELECT
[Year] = YEAR(@date),
[Month] = MONTH(@date),
[DayOfMonth] = DAY(@date),
[DayName] = DATENAME(weekday,@date)
) c
RETURN @s
END
GO
create FUNCTION [dbo].GetHolidays(@year int)
RETURNS TABLE
AS
RETURN (
select dt, dbo.GetHoliday(dt) as Holiday
from (
select dateadd(day, number, convert(varchar,@year) + '-01-01') dt
from master..spt_values
where type='p'
) d
where year(dt) = @year and dbo.GetHoliday(dt) is not null
)
create proc UpdateHolidaysTable
as
if not exists(select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'Holidays')
create table Holidays(dt date primary key clustered, Holiday varchar(50))
declare @year int
set @year = 1990
while @year < year(GetDate()) + 20
begin
insert into Holidays(dt, Holiday)
select a.dt, a.Holiday
from dbo.GetHolidays(@year) a
left join Holidays b on b.dt = a.dt
where b.dt is null
set @year = @year + 1
end
create FUNCTION [dbo].[GetWorkDays](@StartDate DATE = NULL, @EndDate DATE = NULL)
RETURNS INT
AS
BEGIN
IF @StartDate IS NULL OR @EndDate IS NULL
RETURN 0
IF @StartDate >= @EndDate
RETURN 0
DECLARE @Days int
SET @Days = 0
IF year(@StartDate) * 100 + datepart(week, @StartDate) = year(@EndDate) * 100 + datepart(week, @EndDate)
--same week
select @Days = (DATEDIFF(dd, @StartDate, @EndDate))
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
ELSE
--diff weeks
select @Days = (DATEDIFF(dd, @StartDate, @EndDate) + 1)
- (DATEDIFF(wk, @StartDate, @EndDate) * 2)
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
RETURN @Days
END