Typescript 如何在构造类之前定义可用于类的属性（例如，对于工厂方法）？

示例代码：

class User {
  name: String;
  constructor(name: String) {
    this.name = name;
  }
}

User.get = (name):User => {
  return new User(name);
}

// Should return User bob
var user = User.get("bob")

// Should also return User bob
var user = new User("bob")

Property 'get' does not exist on type 'typeof User'.ts(2339)

使用：

class User {
  name: String;
  constructor(name: String) {
    this.name = name;
  }
}

User.get = (name):User => {
  return new User(name);
}

// Should return User bob
var user = User.get("bob")

// Should also return User bob
var user = new User("bob")

Property 'get' does not exist on type 'typeof User'.ts(2339)

错误：

class User {
  name: String;
  constructor(name: String) {
    this.name = name;
  }
}

User.get = (name):User => {
  return new User(name);
}

// Should return User bob
var user = User.get("bob")

// Should also return User bob
var user = new User("bob")

Property 'get' does not exist on type 'typeof User'.ts(2339)

我想知道如何定义此属性，以避免出现此错误。另外，是的，我知道我可以在类用户内部定义get函数，但是出于其他原因，我希望能够在类本身上调用get函数。

将

get

（或者可能

创建

）声明为

用户的静态函数：

class User {

  static get(name: string): User {
    return new User(name);
  }

  name: string;

  constructor(name: string) {
    this.name = name;
  }
}

现在，
constuser=user.get（“bob”）应该可以工作。我希望这很适合你问题的最后一段