Unit testing GoLang Sarama消费者团体嘲笑
我是新手,我也在努力模仿这个呼叫:Unit testing GoLang Sarama消费者团体嘲笑,unit-testing,go,mocking,sarama,testify,Unit Testing,Go,Mocking,Sarama,Testify,我是新手,我也在努力模仿这个呼叫:sarama.NewConsumerGroup(brokers,group,config) 我正在使用“验证”,我的模拟代码当前看起来如下: type MyMockedObjectReciever struct { mock.Mock Receiver } func (m *MyMockedObjectReciever) mockCreateConsumer(brokers []string, group string, config *sar
sarama.NewConsumerGroup(brokers,group,config)
我正在使用“验证”,我的模拟代码当前看起来如下:
type MyMockedObjectReciever struct {
mock.Mock
Receiver
}
func (m *MyMockedObjectReciever) mockCreateConsumer(brokers []string, group string, config *sarama.Config) (sarama.ConsumerGroup, error) {
args := m.Called(brokers, group, config)
return args.Get(0).(sarama.ConsumerGroup), args.Error(1)
}
// mock connection and subscribe
wantConsumer := sarama.NewConsumerGroup
createConsumer = c.mockCreateConsumer
c.On("mockCreateConsumer", []string{testBrokers}, testGroup, wantConfig).Return(wantConsumer, nil).Once()
但我得到了一个错误:
--- FAIL: TestKafkaReceiver (0.00s)
--- FAIL: TestKafkaReceiver/test_a_Kafka_receiver (0.00s)
panic: interface conversion: func([]string, string, *sarama.Config) (sarama.ConsumerGroup, error) is not sarama.ConsumerGroup: missing method Close [recovered]
panic: interface conversion: func([]string, string, *sarama.Config) (sarama.ConsumerGroup, error) is not sarama.ConsumerGroup: missing method Close
我相信我模拟的调用是错误的,但是现在确定还有什么可以做。您可以像下面这样编写模拟消费者,以满足consumergroup对象的要求
// Consumergroup handler
type testConsumerGroupHandler struct {
}
func (C testConsumerGroupHandler) Consume(ctx context.Context, topics []string, handler sarama.ConsumerGroupHandler) error {
return nil
}
func (C testConsumerGroupHandler) Errors() <-chan error {
return nil
}
func (C testConsumerGroupHandler) Close() error {
return nil
}
//Consumergroup处理程序
类型testConsumerGroupHandler结构{
}
func(C testConsumerGroupHandler)Consume(ctx context.context,topics[]string,handler sarama.ConsumerGroupHandler)错误{
归零
}
func(C testConsumerGroupHandler)错误()