Warning: file_get_contents(/data/phpspider/zhask/data//catemap/4/c/56.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Vba Powerpoint切换按钮编译错误:需要表达式_Vba_Powerpoint - Fatal编程技术网

Vba Powerpoint切换按钮编译错误:需要表达式

Vba Powerpoint切换按钮编译错误:需要表达式,vba,powerpoint,Vba,Powerpoint,我试图让一个切换按钮将其标题更改为真或假,这取决于它是真还是假。我一直收到一个错误,上面写着“编译错误:需要表达式”。下面是我正在使用的代码 Private Sub ToggleButton1_Click() If ToggleButton1.Value = True Then ToggleButton1.Caption = "Pressed" Else ToggleButton1.Caption = "Not Pressed" End If End Sub 它带我

我试图让一个切换按钮将其标题更改为真或假,这取决于它是真还是假。我一直收到一个错误,上面写着“编译错误:需要表达式”。下面是我正在使用的代码

Private Sub ToggleButton1_Click() 
If ToggleButton1.Value = True Then 
    ToggleButton1.Caption = "Pressed" 
Else 
    ToggleButton1.Caption = "Not Pressed" 
End If 
End Sub

它带我进入模块1并突出显示一个切换按钮是添加到幻灯片还是在用户表单上?

突出显示一个