Visual studio 2010 在WCF中公开特定字段

我有一节课

[DataContract]
public class Sample 
{
   [DataMember]
   int a;
   [DataMember]
   int b;
   [DataMember]
   int c;
}

Sample sampleMethod1 ()
{
  return new Sample { a =5, b=6 }
}

Sample sampleMethod1 ()
{
  return new Sample { a =15, c=61 }
}

---

现在我想当我的外部客户调用sampleMethod1时，示例类的可见字段是a和c，而不是b。类似地，在sampleMethod2中，您需要这样的东西

  [DataContract]
  [KnownType(typeof(SampleDerived1))]
  [KnownType(typeof(SampleDerived2))]
  public class Sample
  {
    [DataMember]
    public int a;
  }

  [DataContract]
  public class SampleDerived1 : Sample
  {
    [DataMember]
    public int b;
  }

  [DataContract]
  public class SampleDerived2 : Sample
  {
    [DataMember]
    public int c;
  }

Sample sampleMethod1 ()
{
  return new SampleDerived1{ a =5, b=6 }
}

Sample sampleMethod2 ()
{
  return new SampleDerived2{ a =15, c=61 }
}

你的方法应该是这样的

  [DataContract]
  [KnownType(typeof(SampleDerived1))]
  [KnownType(typeof(SampleDerived2))]
  public class Sample
  {
    [DataMember]
    public int a;
  }

  [DataContract]
  public class SampleDerived1 : Sample
  {
    [DataMember]
    public int b;
  }

  [DataContract]
  public class SampleDerived2 : Sample
  {
    [DataMember]
    public int c;
  }

Sample sampleMethod1 ()
{
  return new SampleDerived1{ a =5, b=6 }
}

Sample sampleMethod2 ()
{
  return new SampleDerived2{ a =15, c=61 }
}

---

听起来您希望从每个方法返回不同的类。您能否提供更多信息，说明为什么某些字段在通过特定方法返回对象时会“消失”？这是不可能的，因为您与外部客户共享一份完整的

Sample

类合同。所以你可能应该把它分成两个不同的接口/类。恐怕你需要创建两个类来实现它。