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Xml 使用XPath 1.0仅选择不同的值_Xml_Xpath_Xpath 1.0 - Fatal编程技术网
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Xml 使用XPath 1.0仅选择不同的值

xml xpath

Xml 使用XPath 1.0仅选择不同的值,xml,xpath,xpath-1.0,Xml,Xpath,Xpath 1.0,如何使用XPath 1.0仅返回州的名称='Washington'所在的唯一的城市值 <StateDataSet> <State> <Name>Washington</Name> <City>Seattle</City> <business>Starbucks</business> </State> <State

如何使用XPath 1.0仅返回
州的
名称='Washington'
所在的唯一的
城市
值


<StateDataSet>
    <State>
        <Name>Washington</Name>
        <City>Seattle</City>
        <business>Starbucks</business>
    </State>
    <State>
        <Name>Washington</Name>
        <City>Seattle</City>
        <business>Amazon</business>
    </State>
    <State>
        <Name>Washington</Name>
        <City>Redmond</City>
        <business>Microsoft</business>
    </State>
    <State>
        <Name>Washington</Name>
        <City>Redmond</City>
        <business>Starbucks</business>
    </State>
    <State>
        <Name>Washington</Name>
        <City>Seattle</City>
        <business>Dicks</business>
    </State>
    <State>
        <Name>Alaska</Name>
        <City>Anchorage</City>
        <business>Starbucks</business>
    </State>
    <State>
        <Name>Oregon</Name>
        <City>Portland</City>
        <business>Starbucks</business>
    </State>
    <State>
        <Name>Alaska</Name>
        <City>Gnome</City>
        <business>Starbucks</business>
    </State>
</StateDataSet>


这返回了华盛顿市，但其价值观并非独一无二。我使用

我做错了什么？我的查询基于这个XPath


/StateDataSet/State[Name ='Washington' and 
                    not(City = preceding-sibling::State[Name='Washington']/City)]
             /City


将使用
名称='Washington'
选择
州
元素中唯一的
城市
元素：


<City>Seattle</City>
<City>Redmond</City>


西雅图
雷德蒙


按要求


<City>Seattle</City>
<City>Redmond</City>