Xml 如何在xsd中定义子元素中包含父元素的元素
如何在xsd中定义子元素中包含父元素的元素 以下是一个例子:Xml 如何在xsd中定义子元素中包含父元素的元素,xml,xsd,Xml,Xsd,如何在xsd中定义子元素中包含父元素的元素 以下是一个例子: <score seq="1" type="test" numeric="23"> <option lbound="0" ubound=""> <score seq="1" type="app" numeric="575"> <option lbound="" ubound="0">0</option> </
<score seq="1" type="test" numeric="23">
<option lbound="0" ubound="">
<score seq="1" type="app" numeric="575">
<option lbound="" ubound="0">0</option>
</score>
</option>
</score>
0
像这样:
<?xml version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="score">
<xs:complexType>
<xs:sequence>
<xs:element name="option">
<xs:complexType>
<xs:sequence>
<xs:element name="score">
<xs:complexType>
<xs:sequence>
<xs:element name="option">
<xs:complexType>
<xs:simpleContent>
<xs:extension base="xs:unsignedByte">
<xs:attribute name="lbound" type="xs:string" use="required" />
<xs:attribute name="ubound" type="xs:unsignedByte" use="required" />
</xs:extension>
</xs:simpleContent>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="seq" type="xs:unsignedByte" use="required" />
<xs:attribute name="type" type="xs:string" use="required" />
<xs:attribute name="numeric" type="xs:unsignedShort" use="required" />
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="lbound" type="xs:unsignedByte" use="required" />
<xs:attribute name="ubound" type="xs:string" use="required" />
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="seq" type="xs:unsignedByte" use="required" />
<xs:attribute name="type" type="xs:string" use="required" />
<xs:attribute name="numeric" type="xs:unsignedByte" use="required" />
</xs:complexType>
</xs:element>
</xs:schema>
这里有一个用于任何嵌套级别的选项
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified">
<xs:element name="score">
<xs:complexType>
<xs:sequence>
<xs:element minOccurs="0" maxOccurs="unbounded" ref="option"/>
<xs:element minOccurs="0" maxOccurs="unbounded" ref="ignore"/>
</xs:sequence>
<xs:attribute name="numeric" use="optional" type="xs:integer"/>
<xs:attribute name="seq" use="required" type="xs:integer"/>
<xs:attribute name="type" use="required" type="xs:NCName"/>
</xs:complexType>
</xs:element>
<xs:element name="option">
<xs:complexType mixed="true">
<xs:sequence>
<xs:element minOccurs="0" maxOccurs="unbounded" ref="score"/>
</xs:sequence>
<xs:attribute name="id" use="optional"/>
<xs:attribute name="lbound" use="optional"/>
<xs:attribute name="ubound" use="optional"/>
</xs:complexType>
</xs:element>
<xs:element name="ignore"/>
</xs:schema>
这适用于您给出的两个示例:
示例1
<score seq="1" type="test" numeric="23">
<option lbound="0" ubound="">
<score seq="1" type="app" numeric="575">
<option lbound="" ubound="0">0</option>
</score>
</option>
</score>
0
示例2(摘自评论)
10
从一个示例实例中不可能计算出要在模式中施加哪些约束。例如,是否允许任何级别的分数/选项对嵌套,或者是否希望将其限制为一个级别的嵌套?
<score seq="1" type="IN">
<option id="1">10</option>
<ignore/>
</score>