Actionscript 3 如何通过actionscript 3检查数组中的每个项是否都有第二个数组中的hitTestObject项

我有一个拖放游戏的代码

如何通过actionscript 3检查数组的每个项是否都有hitTestObject第二个数组的项，以便发生其他事情，例如显示一条完成良好的消息

var hitArray:Array = new Array(hitTarget1,hitTarget2,hitTarget3,hitTarget4,hitTarget5);
var dropArray:Array = new Array(drop1,drop2,drop3,drop4,drop5);
var positionsArray:Array = new Array();

for (var i:int = 0; i < dropArray.length; i++) {
    dropArray[i].buttonMode = true;
    dropArray[i].addEventListener(MouseEvent.MOUSE_DOWN, mdown);
    dropArray[i].addEventListener(MouseEvent.MOUSE_UP, mUp);
    positionsArray.push({xPos:dropArray[i].x, yPos:dropArray[i].y});
}

function mdown(e:MouseEvent):void {
    e.currentTarget.startDrag();
    setChildIndex(MovieClip(e.currentTarget), numChildren - 1);
}

function mUp(e:MouseEvent):void {

    var dropIndex:int = dropArray.indexOf(e.currentTarget);
    var target:MovieClip = e.currentTarget as MovieClip;

    target.stopDrag();

    if (target.hitTestObject(hitArray[dropIndex])) {
        target.x = hitArray[dropIndex].x;
        target.y = hitArray[dropIndex].y;
        playSound(sosto);
    }else{
        target.x = positionsArray[dropIndex].xPos;
        target.y = positionsArray[dropIndex].yPos;
    }
}

reset.addEventListener(MouseEvent.CLICK, backObjects);

function backObjects(e:MouseEvent):void{
    for(var i:int = 0; i < dropArray.length; i++){
        if(dropArray[i].x == hitArray[i].x && dropArray[i].y == hitArray[i].y){
            dropArray[i].x = positionsArray[i].xPos;
            dropArray[i].y = positionsArray[i].yPos;
        }
    }
}

function playSound(SoundName:Class):void{
    var sound = new SoundName();
    var channel:SoundChannel = sound.play();
}
playSound(sosto);

var-hitArray:Array=新阵列（hitTarget1、hitTarget2、hitTarget3、hitTarget4、hitTarget5）；
var dropArray:Array=新数组（drop1、drop2、drop3、drop4、drop5）；
变量位置数组：数组=新数组（）；
for（变量i:int=0；i

尝试添加此行：

stage.addEventListener(Event.ENTER_FRAME, loop);

其中“loop”是一个包含其余代码的函数，看起来像

function loop (e:Event):void
{
//Your Code
}

---

祝你好运

让我们创建一个函数，告诉我们是否每个“命中目标”及其对应的“下降”都相互接触

function allCorrect():Boolean {
    //for each item in the hitArray, we repeat the action
    //we assume that length of hitArray and dropArray are the same
    for (var i=0;i<hitArray.length;i++) {
        //if the corresponding target and drop do not hit each other, return false
        if (!(hitArray[i].hitTestObject(dropArray[i])) {
            return false
            //if we return false, this function will continue no further
        }
    }
    //We have cycled through all of the items in the arrays, and none of the
    //hitTestObjects have been false, so we return true
    return true
}

---

希望这能回答你的问题

做一个循环，循环数组a，在每次迭代中测试B的每个元素。点击时显示消息。我需要更多的帮助来理解如何循环数组A，在每次迭代中测试B的每个元素

if (allCorrect()) {
    //display "youz a cool cat, bro"
    //remove all of your event listeners to improve performance
}