Actionscript 3 如何知道类对象引用的是什么类？

我们有类对象（引用类的对象），因此您可以从该类对象创建对象：

var classObject:Class = package.to.class.AClass;
var objectFromClass:AClass = new classObject();

现在，我想知道

classObject

引用了什么对象。例如：

function Creator(classObject:Class):AClass
{
    // here I want to know what class is referenced by classObject
    return new classObject();
}

var classObject:Class = package.to.class.AClass;
var objectFromClass:AClass = Creator(classObject);

var name:String = '';
// name = ''

name = flash.utils.getQualifiedClassName(package.to.class.AClass);
// name = 'AClass'

name = ''
// name = ''

var anInstance:AClass = new AClass();
name = flash.utils.getQualifiedClassName(anInstance);
// name = 'AClass'

这是可行的，但是如果我传递了一个不引用

AClass

的类对象呢？我想知道这件事是否发生了，并对它做点什么

---编辑---

我找到了这个函数

flash.utils.getQualifiedClassName（值：*）：字符串 此函数返回类的名称，例如：

function Creator(classObject:Class):AClass
{
    // here I want to know what class is referenced by classObject
    return new classObject();
}

var classObject:Class = package.to.class.AClass;
var objectFromClass:AClass = Creator(classObject);

var name:String = '';
// name = ''

name = flash.utils.getQualifiedClassName(package.to.class.AClass);
// name = 'AClass'

name = ''
// name = ''

var anInstance:AClass = new AClass();
name = flash.utils.getQualifiedClassName(anInstance);
// name = 'AClass'

因此，我所要做的就是比较该函数的结果：

function Creator(classObject:Class):AClass
{
    var anInstance:AClass = new AClass();
    var className:String = flash.utils.getQualifiedClassName(anInstance);
    var classObjectName:String = flash.utils.getQualifiedClassName(classObject);

    // here className and classObjectName are 'AClass' :)
    if (className != classObjectName)
        throw new Error('The classes are different');

    return new classObject();
}

var classObject:Class = package.to.class.AClass;
var objectFromClass:AClass = Creator(classObject);

---编辑2---

另一种方法是使用对象类的构造函数属性：

function Creator(classObject:Class):AClass
{
    var tempInstance:AClass = new AClass();
    var tempClassObject:Class = Object(tempInstance).constructor;

    if (classObject != tempClassObject)
        throw new Error('The classes are different');

    return new classObject();
}

---

我发现完成此任务最简单（不知道是否最快）的方法是在下一个示例中：

function Creator(classObject:Class):AClass
{
    var anInstance:Object = new classObject() as AClass;
    if (anInstance == null)
        throw new Error('The classes are different');

    return new classObject(); // or return anInstance as AClass;
}

---

如果

AClass

是一个接口，这也适用。

与其强制转换到AClass并检查它是否为null，为什么不使用“is”操作符呢？