Actionscript 3 检测是否"；“玩家”；在AS3中跳到一个盒子上

我正在做一个简单的AS3游戏，玩家应该能够跳到一个盒子上。 如何检测玩家是否落在箱子上而没有撞到箱子

AS3让玩家跳跃：

var grav:Number = 10;
var jumping:Boolean = false;
var jumpPow:Number = 0;

stage.addEventListener(KeyboardEvent.KEY_DOWN, onDown);
stage.addEventListener(Event.ENTER_FRAME, update);

function onDown(evt:KeyboardEvent):void
{
    if(evt.keyCode == Keyboard.UP)
    {

        //umbau das mehrfach tab bis höhe erreicht?
        if(jumping != true)
        {
            jumpPow = -10;
            jumping = true;
        }
    }   
}


function update(evt:Event):void
{
    if(jumping)
    {
        player_mc.y += jumpPow;
        jumpPow += grav;

        if(player_mc.y >= stage.stageHeight)
        {
            jumping = false;
            player_mc.y = stage.stageHeight;
        }
    }
}    

游戏布局是这样的：（灰色框从右向左移动，玩家的位置是固定的）

---

您应该从一个简单的矩形碰撞函数开始：

/* Test collision between a rectangle and another rectangle. */
/* right() and bottom() return x+width and y+height of the parent rectangle. */
Rectangle.prototype.collideRectangle=function(rectangle_){
    if (this.x>rectangle_.right()||this.y>rectangle_.bottom()||this.right()<rectangle_.x||this.bottom()<rectangle_.y){
        return false;
    }
    return true;
}

/*测试一个矩形和另一个矩形之间的冲突*/
/*right（）和bottom（）返回父矩形的x+宽度和y+高度*/
Rectangle.prototype.collideRectangle=函数（矩形）{
如果（this.x>rectangle_124;|||this.y>rectangle_124;.bottom（）| this.right（））
/* If true, the two rectangles are definitely colliding. */
if (red_rect.collideRectangle(gray_rect)){
    /* Get the last position of the bottom of the red rectangle. */
    var old_bottom=red_rect.bottom()-red_rect.velocity.y;
    /* If the old bottom was above the gray rectangle on the last frame and is colliding in this frame, you know that the red rectangle is landing on the gray rectangle. */
    if (old_bottom<gray_rect.y){
        /* Place the red rectangle on top of the gray rectangle. */
        red_rect.y=gray_rect.y-red_rect.height;
    }
}