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Android 我能';不要使用声明的TextView_Android_Android Fragmentactivity - Fatal编程技术网

Android 我能';不要使用声明的TextView

Android 我能';不要使用声明的TextView,android,android-fragmentactivity,Android,Android Fragmentactivity,它无法识别textView,然后我无法使用其方法,因此无法继续。可能会发生什么 布局为: public class DemoActivity extends FragmentActivity{ @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_demo); } Tex

它无法识别textView,然后我无法使用其方法,因此无法继续。可能会发生什么

布局为:

public class DemoActivity extends FragmentActivity{

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_demo);
}
TextView textView = (TextView) findViewById(R.id.demo1);
textview.setText("hi"); 

它不在
onCreate()
中,因此它无法识别,请将其放入
onCreate()


该死!对不起,我20分钟都在想到底是怎么回事。感谢什么都不是,那是可能发生的:)
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >

<TextView 
    android:id="@+id/demo1"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    />

 </LinearLayout>
public class DemoActivity extends FragmentActivity{

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_demo);
    TextView textView = (TextView) findViewById(R.id.demo1);
    textview.setText("hi"); 

}