来自Mapquest-Android应用程序的JSON响应不正确
我正在尝试使用mapquest api从mapquest获取JSON对象,并将其放入Android应用程序中。JSON请求规范如下所示来自Mapquest-Android应用程序的JSON响应不正确,android,json,Android,Json,我正在尝试使用mapquest api从mapquest获取JSON对象,并将其放入Android应用程序中。JSON请求规范如下所示 POST URL: http://www.mapquestapi.com/directions/v2/route?key=[YOUR_KEY_HERE] POST BODY: { locations:[ "State College, PA", "Lancaster, PA" ] } 以下代码成功建立了连接,但mapque
POST URL:
http://www.mapquestapi.com/directions/v2/route?key=[YOUR_KEY_HERE]
POST BODY:
{
locations:[
"State College, PA",
"Lancaster, PA"
]
}
以下代码成功建立了连接,但mapquest的响应不正确
URL url_mapquest = new URL("http://www.mapquestapi.com/directions/v2/route?key=xxxxxxxxxxxx");
HttpURLConnection connection = (HttpURLConnection) url_mapquest.openConnection();
String urlParameters = "None";
connection.setRequestMethod("POST");
connection.setRequestProperty("USER-AGENT", "Mozilla/5.0");
connection.setRequestProperty("ACCEPT-LANGUAGE", "en-US,en;0.5");
connection.setDoOutput(true);
JSONObject jsonParam = new JSONObject();
try {
JSONArray list = new JSONArray();
list.put("State College, PA");
list.put("Lancaster, PA");
jsonParam.put("locations", list);
} catch (JSONException e) {
e.printStackTrace();
}
System.out.println("JSON String: " + jsonParam.toString());
DataOutputStream dStream = new DataOutputStream(connection.getOutputStream());
dStream.writeBytes(jsonParam.toString());
dStream.flush();
dStream.close();
int responseCode = connection.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url_mapquest);
System.out.println("Post parameters : " + urlParameters);
System.out.println("Response Code : " + responseCode);
final StringBuilder output_Mars = new StringBuilder("Request URL : " + url_mapquest);
output_Mars.append(System.getProperty("line.separator") + "Request Parameters : " + urlParameters);
output_Mars.append(System.getProperty("line.separator") + "Response Code : " + responseCode);
output_Mars.append(System.getProperty("line.separator") + "Type : " + "POST");
String line = "";
StringBuilder responseOutput = new StringBuilder();
if (responseCode != HttpURLConnection.HTTP_FORBIDDEN) {
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
System.out.println("output===============" + br);
while ((line = br.readLine()) != null) {
responseOutput.append(line);
}
br.close();
} else {
responseOutput.append("Response Code 403 Forbidden");
}
下面是从android emulator捕获的错误响应
代码中可能有什么错误
参考文献:
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("Accept", "application/json");
emulator响应中的以下注释表明应用程序可能没有正确接收JSON对象
A JSONObject text must begin with a '{' at character 0
有什么方法可以显示您发布到api的JSON(jsonParam.toString())吗?首先,看起来您没有包含所需的路由密钥,但如果看到类似于Ultradiv的JSON,则会有所帮助。@Ultradiv(jsonParam.toString()是{“位置”:[“宾夕法尼亚州州立大学”,“宾夕法尼亚州兰开斯特”]}@卡森先生,我故意把路线钥匙给xxxxx了