在Android上检索联系人图像
我目前正在从事一个android项目,我试图在设备中查找联系人电话号码,并检索联系人姓名和联系人图像等联系人信息。获取合同名称工作正常,但是,在尝试获取照片uri时会抛出空指针 下面是我正在使用的代码:在Android上检索联系人图像,android,android-contacts,Android,Android Contacts,我目前正在从事一个android项目,我试图在设备中查找联系人电话号码,并检索联系人姓名和联系人图像等联系人信息。获取合同名称工作正常,但是,在尝试获取照片uri时会抛出空指针 下面是我正在使用的代码: public ContactInformation getContactInfoFromPhoneNumber(String number) { ContactInformation contactInformation = new ContactInformation(
public ContactInformation getContactInfoFromPhoneNumber(String number)
{
ContactInformation contactInformation = new ContactInformation();
if (number == null)
{
return null;
}
number = number.replace(" ", "");
if (number.startsWith("+"))
{
number = number.substring(3);
}
ContentResolver contentResolver = context.getContentResolver();
Uri uri = ContactsContract.Data.CONTENT_URI;
String[] projection = new String[] {ContactsContract.PhoneLookup._ID, ContactsContract.PhoneLookup.DISPLAY_NAME};
String selection = "REPLACE (" + ContactsContract.CommonDataKinds.Phone.NUMBER + ", \" \" , \"\" ) LIKE ?";
String[] selectionArgs = { "%" + number };
Cursor cursor = contentResolver.query(uri, projection, selection, selectionArgs, null);
if (cursor.moveToFirst())
{
contactInformation.contactName = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.PhoneLookup.DISPLAY_NAME));
contactInformation.photoUri = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.PHOTO_URI));
cursor.close();
return contactInformation;
}
else
{
cursor.close();
return null;
}
}
谢谢你能提供的帮助
更新
下面是我根据伊兹克·萨马拉的答案更新的代码
下面是我如何进行联系人查找的
public ContactInformation getContactInfoFromPhoneNumber(String number)
{
ContactInformation contactInformation = new ContactInformation();
if (number == null)
{
return null;
}
number = number.replace(" ", "");
if (number.startsWith("+"))
{
number = number.substring(3);
}
ContentResolver contentResolver = context.getContentResolver();
Uri uri = ContactsContract.Data.CONTENT_URI;
String[] projection = new String[] {ContactsContract.PhoneLookup._ID, ContactsContract.PhoneLookup.DISPLAY_NAME};
String selection = "REPLACE (" + ContactsContract.CommonDataKinds.Phone.NUMBER + ", \" \" , \"\" ) LIKE ?";
String[] selectionArgs = { "%" + number };
Cursor cursor = contentResolver.query(uri, projection, selection, selectionArgs, null);
if (cursor.moveToFirst())
{
contactInformation.contactName = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.PhoneLookup.DISPLAY_NAME));
contactInformation.photoBase64String = getContactPhoto(cursor.getInt(cursor.getColumnIndexOrThrow(ContactsContract.Contacts._ID)));
cursor.close();
return contactInformation;
}
else
{
cursor.close();
return null;
}
}
下面是我的getContactPhoto函数
private String getContactPhoto(int contactID)
{
Uri contactUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, contactID);
Uri photoUri = Uri.withAppendedPath(contactUri, ContactsContract.Contacts.Photo.CONTENT_DIRECTORY);
Cursor cursor = context.getContentResolver().query(photoUri, new String[]{ContactsContract.Contacts.Photo.PHOTO},
null, null, null);
if (cursor == null)
{
return null;
}
if (cursor.getCount() > 0)
{
while (cursor.moveToNext()) {
byte[] data = cursor.getBlob(0);
String base64String = Base64.encodeToString(data, Base64.DEFAULT);
cursor.close();
return base64String;
}
}
return null;
}
它在if语句中失败,并直接跳出if返回null,就好像游标中没有任何内容一样 此功能适用于我:
private byte[] getContactPhoto(Context context,long contact_id) {
Uri contactUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, contact_id);
Uri photoUri = Uri.withAppendedPath(contactUri,ContactsContract.Contacts.Photo.CONTENT_DIRECTORY);
Cursor cursor = context.getContentResolver().query(photoUri, new String[]{ContactsContract.Contacts.Photo.PHOTO}, null, null, null);
if(cursor == null)
return null;
try {
if(cursor.getCount() > 0) {
if (cursor.moveToFirst()) {
byte[] data = cursor.getBlob(0);
cursor.close();
if (data != null)
return data;
}
}
}
finally {
cursor.close();
}
return null;
}
private void getContacts(Context context) {
ContentResolver cr = context.getContentResolver();
Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI,null,null,null,null);
try {
if (cursor.getCount() > 0) {
while (cursor.moveToNext()) {
long contact_id = cursor.getLong(cursor.getColumnIndex(ContactsContract.Contacts._ID));
Contact friend = new Contact();
String name= cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String email = getContactEmail(context, contact_id);
if(!name.contains("@") && !email.matches("")) {
friend.setName(name);
friend.setEmail(email);
friend.setImage(getContactPhoto(context, contact_id));
friend.setPhone(getContactMobilePhoneNumber(context, contact_id));
mContacts.add(friend);
}
}
}
}
finally {
cursor.close();
}
}
这需要任何特殊权限吗?联系方式是什么?权限:谢谢,似乎仍然不起作用,请检查我的问题