android中xml解析器的响应
我在android中使用SAX解析器从url获取xml数据,但仍然无法获取响应的存储位置 代码: 我的问题是响应存储在哪里,以及如何访问它以从xml获得所需的信息 编辑:非常感谢你们的帮助。。现在我明白了逻辑。。但我面临另一个问题 代码:android中xml解析器的响应,android,xml,Android,Xml,我在android中使用SAX解析器从url获取xml数据,但仍然无法获取响应的存储位置 代码: 我的问题是响应存储在哪里,以及如何访问它以从xml获得所需的信息 编辑:非常感谢你们的帮助。。现在我明白了逻辑。。但我面临另一个问题 代码: String c = city.getText().toString(); String s = state.getText().toString(); try { SAXParserFactory factory = SAXP
String c = city.getText().toString();
String s = state.getText().toString();
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser parser = factory.newSAXParser();
XMLReader reader = parser.getXMLReader();
HandlingXMLStuff handler = new HandlingXMLStuff();
reader.setContentHandler(handler);
String query = URLEncoder.encode(
"http://api.openweathermap.org/data/2.5/weather?mode=xml&q="
+ c + "," + s, "utf-8");
URL url = new URL("http://api.openweathermap.org/data/2.5/weather?mode=xml&q="
+ c + "," + s);
HttpURLConnection connection = (HttpURLConnection) url
.openConnection();
reader.parse(new InputSource(connection.getInputStream()));
String information = handler.getInformation();
output.setText(information);
} catch (Exception e) {
output.setText(e.toString());
}
我没有收到来自url的响应,错误是无法将null解析为int。知道发生了什么吗??我在浏览器中输入了相同的url,得到了正确的响应,但在这里不起作用
编辑:修正。我的处理程序函数xD中出现了一些错误
feedParser oFeedParser = new feedParser(MainActivity.this);
try {
/**
* Create a new instance of the SAX parser
**/
SAXParserFactory saxPF = SAXParserFactory.newInstance();
SAXParser saxP = saxPF.newSAXParser();
XMLReader xmlR = saxP.getXMLReader();
URL url = new URL("Your_URL"); // URL of the XML
xmlR.setContentHandler(oFeedParser);
xmlR.parse(new InputSource(url.openStream()));
handler.sendEmptyMessage(0);
} catch(IOException e) {
System.out.println(e);
handler.sendEmptyMessage(1);
} catch (Exception e) {
System.out.println(e);
} finally {
oFeedParser.closeDataBase();
}
}
和feedParser类
public class feedParser extends DefaultHandler {
String elementValue = null;
boolean elementOn, isFeedInitialized = false;
feed oFeed;
feedsDAO dao;
public feedParser(Context context) {
dao = new feedsDAO(context);
dao.open();
}
public void closeDataBase() {
dao.close();
}
/**
* This will be called when the tags of the XML starts.
**/
@Override
public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
if (localName.equals("ITEM_NAME")) {
}
}
/**
* This will be called when the tags of the XML end.
**/
@Override
public void endElement(String uri, String localName, String qName) throws SAXException {
if (localName.equals("ITEM_NAME")) {
}
}
/**
* This is called to get the tags value
**/
@Override
public void characters(char[] ch, int start, int length)
throws SAXException {
if (elementOn) {
elementValue = new String(ch, start, length);
elementOn = false;
}
}
}
检查您是否研究过Android的HTTP请求?如果没有,那么首先阅读它,以便更好地理解HTTPRequest以及如何获得它的响应
public class feedParser extends DefaultHandler {
String elementValue = null;
boolean elementOn, isFeedInitialized = false;
feed oFeed;
feedsDAO dao;
public feedParser(Context context) {
dao = new feedsDAO(context);
dao.open();
}
public void closeDataBase() {
dao.close();
}
/**
* This will be called when the tags of the XML starts.
**/
@Override
public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
if (localName.equals("ITEM_NAME")) {
}
}
/**
* This will be called when the tags of the XML end.
**/
@Override
public void endElement(String uri, String localName, String qName) throws SAXException {
if (localName.equals("ITEM_NAME")) {
}
}
/**
* This is called to get the tags value
**/
@Override
public void characters(char[] ch, int start, int length)
throws SAXException {
if (elementOn) {
elementValue = new String(ch, start, length);
elementOn = false;
}
}
}