如何在Android Studio中使用HTTP Post发送参数

我想使用HTTP Post方法发送两个以上的参数

这是我的ServiceHandler.java

import java.io.IOException;
import java.io.UnsupportedEncodingException;
import java.util.List;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;

public class ServiceHandler {

    static String response = null;
    public final static int GET = 1;
    public final static int POST = 2;

    public ServiceHandler() {

    }

    /**
     * Making service call
     * @url - url to make request
     * @method - http request method
     * */
    public String makeServiceCall(String url, int method) {
        return this.makeServiceCall(url, method, null);
    }

    /**
     * Making service call
     * @url - url to make request
     * @method - http request method
     * @params - http request params
     * */
    public String makeServiceCall(String url, int method,
                                  List<NameValuePair> params) {
        try {
            // http client
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpEntity httpEntity = null;
            HttpResponse httpResponse = null;

            // Checking http request method type
            if (method == POST) {
                HttpPost httpPost = new HttpPost(url);
                // adding post params
                if (params != null) {
                    httpPost.setEntity(new UrlEncodedFormEntity(params));
                }

                httpResponse = httpClient.execute(httpPost);

            } else if (method == GET) {
                // appending params to url
                if (params != null) {
                    String paramString = URLEncodedUtils
                            .format(params, "utf-8");
                    url += "?" + paramString;
                }
                HttpGet httpGet = new HttpGet(url);

                httpResponse = httpClient.execute(httpGet);

            }
            httpEntity = httpResponse.getEntity();
            response = EntityUtils.toString(httpEntity);

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        return response;

    }
}

现在如何发送参数。例如，我需要发送一个值为xyz的参数abc

谢谢

试试看

HttpPost httpPost = new HttpPost(url);
// adding post params 
List<NameValuePair> params = new ArrayList<NameValuePair>(2);
params.add(new BasicNameValuePair("abc", "xyz"));
if (params != null) {
    httpPost.setEntity(new UrlEncodedFormEntity(params));
}
httpResponse = httpClient.execute(httpPost

HttpPost-HttpPost=新的HttpPost（url）；
//添加post参数
列表参数=新的ArrayList（2）；
参数添加（新的BasicNameValuePair（“abc”、“xyz”）；
如果（参数！=null）{
setEntity（新的UrlEncodedFormEntity（参数））；
}
httpResponse=httpClient.execute（httpPost

我想从我的活动而不是从ServiceHandler.java发送参数。有可能吗？所以试试

列出params=new ArrayList（）；params.add（new BasicNameValuePair（“abc”，“xyz”）；

sh.makeServiceCall（url，ServiceHandler.POST，params）；你能把代码发送到Thungle吗。it@gmail.com.我会在这里查看更多！

HttpPost httpPost = new HttpPost(url);
// adding post params 
List<NameValuePair> params = new ArrayList<NameValuePair>(2);
params.add(new BasicNameValuePair("abc", "xyz"));
if (params != null) {
    httpPost.setEntity(new UrlEncodedFormEntity(params));
}
httpResponse = httpClient.execute(httpPost