Android 每5秒用字符串数组中的每个字符串更新TextView
我有一个Android 每5秒用字符串数组中的每个字符串更新TextView,android,arrays,string,countdowntimer,Android,Arrays,String,Countdowntimer,我有一个TextView,我想每隔5秒钟用字符串数组中的每个字符串更新TextView 这是我试过的代码。它始终仅显示字符串数组中的最后一个字符串 TextView display; EditText caption; Thread thread; String blinks; String[] wc; private CountDownTimer timer; @Override protected void onCreate(Bundle savedInstanceState) {
TextView
,我想每隔5秒钟用字符串数组中的每个字符串更新TextView
这是我试过的代码。它始终仅显示字符串数组中的最后一个字符串
TextView display;
EditText caption;
Thread thread;
String blinks;
String[] wc;
private CountDownTimer timer;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
display = (TextView) findViewById(R.id.display);
caption = (EditText) findViewById(R.id.caption);
timer = new CountDownTimer(5000, 20) {
@Override
public void onTick(long millisUntilFinished) {
String[] wc = {"The","Qucik", "Brown","fox","Jumped"};
for (int j = 0; j < wc.length; j++) {
blinks = wc[j];
final String[] titles = {"" + blinks + ""};
for (int i = 0; i < titles.length; i++) {
display.setText(titles[i]);
}
}
}
@Override
public void onFinish() {
try{
yourMethod();
}catch(Exception e){
}
}
}.start();
}
TextView显示;
编辑文本标题;
螺纹;
字符串闪烁;
字符串[]wc;
私人倒计时;
@凌驾
创建时受保护的void(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
display=(TextView)findViewById(R.id.display);
caption=(EditText)findViewById(R.id.caption);
计时器=新的倒计时计时器(5000,20){
@凌驾
公共void onTick(长毫秒未完成){
String[]wc={“The”,“Qucik”,“Brown”,“fox”,“Jumped”};
对于(int j=0;j
试着在android中使用handler,我想你是这样的:
String[] wc = {"The","Qucik", "Brown","fox","Jumped"};
int j = 0;
Handler handler = new Handler();
Runnable runit = new Runnable() {
@Override
public void run() {
try{
for (; j < wc.length; j++) {
blinks = wc[j];
final String[] titles = {"" + blinks + ""};
for (int i = 0; i < titles.length; i++) {
display.setText(titles[i]);
}
handler.postDelayed(this,5000);
}
}
catch (Exception e) {
// handle exception
}
}
};
handler.postDelayed(runit, 5000);
String[]wc={“The”,“Qucik”,“Brown”,“fox”,“hopped”};
int j=0;
Handler=newhandler();
Runnable runit=new Runnable(){
@凌驾
public void run(){
试一试{
对于(;j
- 问题:for循环的最后一次迭代(在j上)将文本设置为最后一个字符串
TextView.setText()
。然后您可以使用您的方法(CountDownTimer
)或(Handler
)。根据您的方法,这将类似于:
int counter = 0; // field member, NOT local variable
@Override
public void onTick(long millisUntilFinished) {
display.setText("{" + wc[counter++] + "}");
if (counter == 5) counter = 0;
}
如果答案有用。请投票:)
在这里使用Handler要简单得多。你能使它无限循环吗?要使它无限循环,只需重置计数器,如:
display.setText(wc[i++]);如果(i==wc.length){i=0;}handler.postDelayed(这个,5000)代码>
int counter = 0; // field member, NOT local variable
@Override
public void onTick(long millisUntilFinished) {
display.setText("{" + wc[counter++] + "}");
if (counter == 5) counter = 0;
}
final String[] gritArray = getResources().getStringArray(R.array.gritInformation);
//creating new handler allows send and process message
final Handler gritInfoHanlder = new Handler();
//adding runnable to message queque
gritInfoHanlder.post(new Runnable() {
//initializing array position
int tipPosition = 0;
@Override
public void run() {
//set number of tip(randon/another way)
//setting array to textview
gritInfo.setText(gritArray[tipPosition]);
tipPosition++;
//if array exist its length remove callback
if (tipPosition == gritArray.length) {
gritInfoHanlder.removeCallbacks(this);
//delayed handler 10 sec
} else {
gritInfoHanlder.postDelayed(this, 1000 * 10);
}
}
});