Android 随机开关盒

你好，朋友，我有两种情况，但我想随机做。当用户点击按钮，则有2种情况case0或case1随机变化。所以文本也是随机变化的

*lastImageName和lastImageName2是变量字符串

Random rand = new Random();
int newrand = rand.nextInt(1) + 1;

switch(newrand) {
case 0:
    text1.setText(lastImageName);
    text2.setText(lastImageName2);
    break;
case 1:
    text1.setText(lastImageName2);
    text2.setText(lastImageName);
    break;
}

---

但这有时是行不通的。。兰特是多少。问题？

卸下+1。只要这样做：

intnewrand=rand.nextInt（2）
生成一个介于0（包括0）和上限（排除）之间的随机数。即，
nextInt（1）
将始终返回
0
。相反，您应该只使用：

int newrand = rand.nextInt(2);

如果您只有两个案例，则使用

boolean state = rand.nextBoolean();
text1.setText(state?lastImageName:lastImageName2);
text2.setText(state?lastImageName2:lastImageName);

对于多个，您也可以使用

Random rand = new Random();
int newrand = rand.nextInt() % count;//count = 2 for your case

switch(newrand) {
case 0:
    text1.setText(lastImageName);
    text2.setText(lastImageName2);
    break;
case 1:
    text1.setText(lastImageName2);
    text2.setText(lastImageName);
    break;
}

Random rand = new Random();
int newrand = rand.nextInt() % count;//count = 2 for your case

switch(newrand) {
case 0:
    text1.setText(lastImageName);
    text2.setText(lastImageName2);
    break;
case 1:
    text1.setText(lastImageName2);
    text2.setText(lastImageName);
    break;
}