Android 两个位置之间的距离为'；不对

我已经使用上的算法来计算两点之间的距离

我的两点是

long1 = 51.507467;
lat1 = -0.08776;

long2 = 51.508736;
lat2 = -0.08612;

根据答案是0.1812公里

我的应用程序给出的结果（

d

）为0.230km

检查哈弗森公式：

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您的实现是正确的。给定这些经纬度的距离应产生

0.230 km

。但是，坐标的正常输入是（纬度、经度）。将它们向后放置（经度、纬度）会产生不正确的距离

0.1812 km

为什么要重新发明自己的距离计算器，类中内置了一个

退房

distanceBetween(double startLatitude, double startLongitude, double endLatitude, double endLongitude, float[] results) 
Computes the approximate distance in meters between two locations, and optionally the initial and final bearings of the shortest path between them.

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Ally你的概念是对的。这行可能有点变化

double c=2*Math.asin（Math.sqrt（a））
哦。。。有点尴尬。谢谢你的帮助：）
distanceBetween(double startLatitude, double startLongitude, double endLatitude, double endLongitude, float[] results) 
Computes the approximate distance in meters between two locations, and optionally the initial and final bearings of the shortest path between them.

public double CalculationByDistance(GeoPoint StartP, GeoPoint EndP) {  
  double lat1 = StartP.getLatitudeE6()/1E6;  
  double lat2 = EndP.getLatitudeE6()/1E6;  
  double lon1 = StartP.getLongitudeE6()/1E6;  
  double lon2 = EndP.getLongitudeE6()/1E6;  
  double dLat = Math.toRadians(lat2-lat1);  
  double dLon = Math.toRadians(lon2-lon1);  
  double a = Math.sin(dLat/2) * Math.sin(dLat/2) +  
     Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) *  
     Math.sin(dLon/2) * Math.sin(dLon/2);  
  double c = 2 * Math.asin(Math.sqrt(a));  
  return Radius * c;  
 }