Android从通话记录中获取联系人图片
在查询Android从通话记录中获取联系人图片,android,contacts,android-contacts,calllog,Android,Contacts,Android Contacts,Calllog,在查询People.CONTENT\u URI时,通过简单的 People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId) 因为我知道联系人Id。现在我需要在访问通话记录后做同样的事情。与: String[] strFields = { android.provider.CallLog.Calls.CACHED_NAME,
People.CONTENT\u URI
时,通过简单的
People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId)
因为我知道联系人Id。现在我需要在访问通话记录后做同样的事情。与:
String[] strFields = {
android.provider.CallLog.Calls.CACHED_NAME,
android.provider.CallLog.Calls.NUMBER,
};
String strUriCalls="content://call_log/calls";
Uri UriCalls = Uri.parse(strUriCalls);
Cursor cursorLog = this.getContentResolver().query(UriCalls, strFields, null, null, null);
我从呼叫日志中获取列表,但我找不到任何方法将其与加载照片所需的联系人id链接。该应用程序从api级别4+开始工作
感谢您的帮助。多谢各位
在克里斯蒂安的指导下,适合我的解决方案是:
private long getContactIdFromNumber(String number) {
String[] projection = new String[]{Contacts.Phones.PERSON_ID};
Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL,Uri.encode(number));
Cursor c = getContentResolver().query(contactUri, projection, null, null, null);
if (c.moveToFirst()) {
long contactId=c.getLong(c.getColumnIndex(Contacts.Phones.PERSON_ID));
return contactId;
}
return -1;
}
然后,您必须尝试使用查询的呼叫日志字段获取联系人ID。因此,您可以实现如下内容:
private String getContactIdFromNumber(String number) {
String[] projection = new String[]{Contacts.Phones._ID};
Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL,
Uri.encode(number));
Cursor c = getContentResolver().query(contactUri, projection,
null, null, null);
if (c.moveToFirst()) {
String contactId=c.getString(c.getColumnIndex(Contacts.Phones._ID));
return contactId;
}
return null;
}
然后,您可以使用该联系人ID获取照片。在您的案例中,类似这样的情况:
cursorLog.moveToFirst();
String number = cursorLog.getString(cursorLog.getColumnIndex(android.provider.CallLog.Calls.NUMBER));
contactId = getContactIdFromNumber(number)
People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId);
// blah blah blah
我是这样做的:
ContentResolver cr=this.getContentResolver();
Cursor cc = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
while (cc.moveToNext())
{
contactId = cc.getString(cc.getColumnIndex(ContactsContract.Contacts._ID));
Uri contactPhotoUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, Long.parseLong(contactId));
InputStream is=ContactsContract.Contacts.openContactPhotoInputStream(cr, contactPhotoUri);
//blah-blah
}
这个对我来说很好
private void contactPickedFromLog(Intent data) {
// TODO Auto-generated method stub
String contactNumber = data.getStringExtra(CONTACT_NUMBER);
Cursor cursor = getContentResolver().query(
Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI,
Uri.decode(contactNumber)),
new String[] { PhoneLookup._ID }, null, null, null);
if(cursor.moveToFirst()){
long contactId = cursor.getLong(0);
InputStream inputStream = Contacts.openContactPhotoInputStream(
getContentResolver(),
ContentUris.withAppendedId(Contacts.CONTENT_URI, contactId));
if(inputStream!=null)
Bitmap bitmap = BitmapFactory.decodeStream(inputStream);
}
}
试试这个
public Bitmap getPhoto(String phoneNumber) {
Uri phoneUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
Uri photoUri = null;
ContentResolver cr = getContentResolver();
Cursor contact = cr.query(phoneUri,
new String[] { ContactsContract.Contacts._ID }, null, null, null);
if (contact.moveToFirst()) {
long userId = contact.getLong(contact.getColumnIndex(ContactsContract.Contacts._ID));
photoUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, userId);
}
else {
Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
return getCircleBitmap(defaultPhoto);
}
if (photoUri != null) {
InputStream input = ContactsContract.Contacts.openContactPhotoInputStream(
cr, photoUri);
if (input != null) {
return getCircleBitmap(BitmapFactory.decodeStream(input));
}
} else {
Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
return getCircleBitmap(defaultPhoto);
}
Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
contact.close();
return defaultPhoto;
}
以上答案都是正确的。你也可以通过这个 c、 getString(c.getColumnIndex(CallLog.Calls.CACHED_PHOTO_URI)) 在SDK中工作>=23 如果您正在使用最小SDK
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(num));
uri = ((phone_uri != null) ? Uri.parse(phone_uri) : uri);
Cursor cursor = getContext().getContentResolver().query(uri, null, null, null, null);
if (cursor != null) {
if (cursor.moveToNext()) {
String id = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup._ID));
String name = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
image_uri = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.PHOTO_URI));
Log.d(TAG, "name " + name + " id "+id+" image_uri "+ image_uri);
}
cursor.close();
}
这个解决方案似乎正是我想要做的。唯一的问题是它没有返回正确的id。例如,对于id为110的联系人,它返回id 713。我确信110是正确的,因为它加载了id为110的正确照片。我错过什么了吗?谢谢大家的支持。啊,不要使用Contacts.Phones.\u ID,如果我使用Contacts.Phones.PERSON\u ID,它会工作的。谢谢你,克里斯蒂安,但是你如何从给定的某个电话号码中获得图片呢?@Alin:不幸的是,给定的电话号码可以分配给多个联系人,甚至有些联系人根本没有电话,所以依靠电话号码真的不可能获得图片。我的意思是,只能为给定的电话号码定义一组图片(可能是空集)。