Android从通话记录中获取联系人图片

Android从通话记录中获取联系人图片,android,contacts,android-contacts,calllog,Android,Contacts,Android Contacts,Calllog,在查询People.CONTENT\u URI时,通过简单的 People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId) 因为我知道联系人Id。现在我需要在访问通话记录后做同样的事情。与: String[] strFields = { android.provider.CallLog.Calls.CACHED_NAME,

在查询
People.CONTENT\u URI
时,通过简单的

People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId)
因为我知道联系人Id。现在我需要在访问通话记录后做同样的事情。与:

String[] strFields = {
                android.provider.CallLog.Calls.CACHED_NAME,
                android.provider.CallLog.Calls.NUMBER, 
                };

        String strUriCalls="content://call_log/calls"; 

            Uri UriCalls = Uri.parse(strUriCalls); 

            Cursor cursorLog = this.getContentResolver().query(UriCalls, strFields, null, null, null);
我从呼叫日志中获取列表,但我找不到任何方法将其与加载照片所需的联系人id链接。该应用程序从api级别4+开始工作

感谢您的帮助。多谢各位

在克里斯蒂安的指导下,适合我的解决方案是:

 private long getContactIdFromNumber(String number) {
        String[] projection = new String[]{Contacts.Phones.PERSON_ID};
        Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL,Uri.encode(number));
        Cursor c = getContentResolver().query(contactUri, projection, null, null, null);

        if (c.moveToFirst()) {
            long contactId=c.getLong(c.getColumnIndex(Contacts.Phones.PERSON_ID));
            return contactId;
        }
        return -1;
    }

然后,您必须尝试使用查询的呼叫日志字段获取联系人ID。因此,您可以实现如下内容:

private String getContactIdFromNumber(String number) {
    String[] projection = new String[]{Contacts.Phones._ID};
    Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL,
        Uri.encode(number));
    Cursor c = getContentResolver().query(contactUri, projection,
        null, null, null);
    if (c.moveToFirst()) {
        String contactId=c.getString(c.getColumnIndex(Contacts.Phones._ID));
        return contactId;
    }
    return null;
}
然后,您可以使用该联系人ID获取照片。在您的案例中,类似这样的情况:

cursorLog.moveToFirst();
String number = cursorLog.getString(cursorLog.getColumnIndex(android.provider.CallLog.Calls.NUMBER));
contactId = getContactIdFromNumber(number)
People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId);
// blah blah blah

我是这样做的:

ContentResolver cr=this.getContentResolver();
Cursor cc = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
while (cc.moveToNext())
{
    contactId = cc.getString(cc.getColumnIndex(ContactsContract.Contacts._ID));
    Uri contactPhotoUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, Long.parseLong(contactId));
    InputStream is=ContactsContract.Contacts.openContactPhotoInputStream(cr, contactPhotoUri);
    //blah-blah
}

这个对我来说很好

private void contactPickedFromLog(Intent data) {
    // TODO Auto-generated method stub
    String contactNumber = data.getStringExtra(CONTACT_NUMBER);
    Cursor cursor = getContentResolver().query(
            Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI,
                    Uri.decode(contactNumber)),
            new String[] { PhoneLookup._ID }, null, null, null);
    if(cursor.moveToFirst()){
    long contactId = cursor.getLong(0);
    InputStream inputStream = Contacts.openContactPhotoInputStream(
            getContentResolver(),
            ContentUris.withAppendedId(Contacts.CONTENT_URI, contactId));
    if(inputStream!=null)
    Bitmap bitmap = BitmapFactory.decodeStream(inputStream);
    }
}  
试试这个

public Bitmap getPhoto(String phoneNumber) {
    Uri phoneUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
    Uri photoUri = null;
    ContentResolver cr = getContentResolver();
    Cursor contact = cr.query(phoneUri,
            new String[] { ContactsContract.Contacts._ID }, null, null, null);

    if (contact.moveToFirst()) {
        long userId = contact.getLong(contact.getColumnIndex(ContactsContract.Contacts._ID));
        photoUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, userId);

    }
    else {
        Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
        return getCircleBitmap(defaultPhoto);
    }
    if (photoUri != null) {
        InputStream input = ContactsContract.Contacts.openContactPhotoInputStream(
                cr, photoUri);
        if (input != null) {
            return getCircleBitmap(BitmapFactory.decodeStream(input));
        }
    } else {
        Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
        return getCircleBitmap(defaultPhoto);
    }
    Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
    contact.close();
    return defaultPhoto;
}

以上答案都是正确的。你也可以通过这个

c、 getString(c.getColumnIndex(CallLog.Calls.CACHED_PHOTO_URI))

在SDK中工作>=23

如果您正在使用最小SDK

Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(num));
        uri = ((phone_uri != null) ? Uri.parse(phone_uri) : uri);
        Cursor cursor = getContext().getContentResolver().query(uri, null, null, null, null);

        if (cursor != null) {
            if (cursor.moveToNext()) {
                String id = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup._ID));
                String name = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
                image_uri = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.PHOTO_URI));
                Log.d(TAG, "name " + name + " id "+id+" image_uri "+ image_uri);
            }
            cursor.close();
        }

这个解决方案似乎正是我想要做的。唯一的问题是它没有返回正确的id。例如,对于id为110的联系人,它返回id 713。我确信110是正确的,因为它加载了id为110的正确照片。我错过什么了吗?谢谢大家的支持。啊,不要使用Contacts.Phones.\u ID,如果我使用Contacts.Phones.PERSON\u ID,它会工作的。谢谢你,克里斯蒂安,但是你如何从给定的某个电话号码中获得图片呢?@Alin:不幸的是,给定的电话号码可以分配给多个联系人,甚至有些联系人根本没有电话,所以依靠电话号码真的不可能获得图片。我的意思是,只能为给定的电话号码定义一组图片(可能是空集)。