Android 谷歌地图V2：根据地址搜索一个地方；没有经纬度

所以我已经搜索了很多关于在谷歌地图上显示一个地方的内容，但是所有的教程都显示了一种需要纬度和经度的技术，但是有人能告诉我一个技巧，在哪里我可以只用地址字符串来实现这一点吗？谢谢你

我不知道你在android编程方面有多出色，但是，有一个名为AutoCompleteTextView的组件，如果你将其适配器设置为底部代码，它将连接到google maps places并搜索你在AutoCompleteTextView中键入的地址

public class PlacesAutoCompleteAdapter extends ArrayAdapter<String> implements Filterable {
    private static final String LOG_TAG = "Test";
    private static final String PLACES_API_BASE = "https://maps.googleapis.com/maps/api/place";
    private static final String TYPE_AUTOCOMPLETE = "/autocomplete";
    private static final String OUT_JSON = "/json";

    private static final String API_KEY = "Your_Api_Key";


    private ArrayList<String> resultList;
    public static ArrayList<String> refList=null;
    public PlacesAutoCompleteAdapter(Context context, int textViewResourceId) {
        super(context, textViewResourceId);
    }

    @Override
    public int getCount() {
        return resultList.size();
    }

    @Override
    public String getItem(int index) {
        return resultList.get(index);
    }

    @Override
    public Filter getFilter() {
        Filter filter = new Filter() {
            @Override
            protected FilterResults performFiltering(CharSequence constraint) {
                FilterResults filterResults = new FilterResults();
                if (constraint != null) {
                    // Retrieve the autocomplete results.
                    resultList = autocomplete(constraint.toString());

                    // Assign the data to the FilterResults
                    filterResults.values = resultList;
                    filterResults.count = resultList.size();
                }
                return filterResults;
            }

            @Override
            protected void publishResults(CharSequence constraint, FilterResults results) {
                if (results != null && results.count > 0) {

                    notifyDataSetChanged();
                }
                else {
                    notifyDataSetInvalidated();
                }
            }};
        return filter;
    }

    private ArrayList<String> autocomplete(String input) {
        ArrayList<String> resultList = null;
        refList=new ArrayList<String>();
        HttpURLConnection conn = null;
        StringBuilder jsonResults = new StringBuilder();
        try {
            StringBuilder sb = new StringBuilder(PLACES_API_BASE + TYPE_AUTOCOMPLETE + OUT_JSON);
            sb.append("?sensor=false&key=" + API_KEY);
            sb.append("&components=country:tr");
            sb.append("&language=tr");
            sb.append("&input=" + URLEncoder.encode(input, "utf8"));

            URL url = new URL(sb.toString());
            conn = (HttpURLConnection) url.openConnection();
            InputStreamReader in = new InputStreamReader(conn.getInputStream());

            // Load the results into a StringBuilder
            int read;
            char[] buff = new char[1024];
            while ((read = in.read(buff)) != -1) {
                jsonResults.append(buff, 0, read);
            }
        } catch (MalformedURLException e) {
            Log.e(LOG_TAG, "Error processing Places API URL", e);
            return resultList;
        } catch (IOException e) {
            Log.e(LOG_TAG, "Error connecting to Places API", e);
            return resultList;
        } finally {
            if (conn != null) {
                conn.disconnect();
            }
        }

        try {
            // Create a JSON object hierarchy from the results
            JSONObject jsonObj = new JSONObject(jsonResults.toString());
            JSONArray predsJsonArray = jsonObj.getJSONArray("predictions");

            // Extract the Place descriptions from the results
            resultList = new ArrayList<String>(predsJsonArray.length());
            for (int i = 0; i < predsJsonArray.length(); i++) {
                resultList.add(predsJsonArray.getJSONObject(i).getString("description"));
                refList.add(predsJsonArray.getJSONObject(i).getString("reference"));
            }
        } catch (JSONException e) {
            Log.e(LOG_TAG, "Cannot process JSON results", e);
        }

        return resultList;
    }
}

请看一下Android中的。该API包括反向地理编码。也就是说，如果找到结果，则提供一个地址并获得对象的ArrayList作为响应。这个地址包含关于那个地方的所有必要数据

您可以这样使用它：

if(GeoCoder.isPresent()) {

    Geocoder geocoder = new Geocoder(this);
    List<Address> addresses = null;
    try {
        addresses = geocoder.getFromLocationName(YOURADDRESS, 5);
        if (!addresses.isEmpty()) {
            Address address = list.get(0);
            // do something with your address
        } else {
            // No results for your location
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
}

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问题是我想根据位置在地图上添加一个标记，但我不想使用纬度和经度，我想使用字符串地址，你能帮我吗@瓦伦巴夫这是不可能的。要在特定位置放置标记，必须使用lat lng。