Android：从片段中删除SQLIte数据库中的记录行

我在回收视图中有CardView。长按CardView时，将打开一个对话框片段，确认删除CardView及其来自SQLite数据库的数据。单击“确定”后，对话框关闭，DatabaseHelper文件中的“deletefromDB”方法设置为从数据库中的表中删除记录行。该方法使用CARDNUM列及其CARDNUM整数值来删除数据的记录行。虽然对话框按预期关闭，但不幸的是，当我在运行应用程序后检查数据库时，SQLite数据库中没有任何更改（我正在使用DB Browser for SQLite检查前后的数据库）。我错过了什么

DeleteCardViewFragment.java
public class DeleteCardViewFragment extends DialogFragment {

    DatabaseHelper dbHelper;
    private int cardnum = 0;


    public DeleteCardViewFragment() {
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
           Bundle savedInstanceState) {

    dbHelper = new DatabaseHelper(getActivity());
    final View rootView = inflater.inflate(R.layout.delcardview_layout, container, false);
    getDialog().setTitle("Delete skycard");
    ...
    Button btnOK = (Button) rootView.findViewById(R.id.btnOK);
    btnOK.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            **dbHelper.deletefromDB(cardnum);**                
            dismiss();
        }
    });

    return rootView;
    }
} 

数据库表名称和列的DBContract.java文件

public final class DBContract {
public DBContract() {}

public static abstract class DBEntry implements BaseColumns {
    public static final String TABLE_NAME_USERINPUTS = "userinputs";
    public static final String COLUMN_NAME_ID = "_id";
    public static final String COLUMN_NAME_CARDNUM = "cardnum";
    public static final String COLUMN_NAME_TODO = "todo";
    public static final String COLUMN_NAME_NOTE1 = "note1";
    public static final String COLUMN_NAME_NOTE2 = "note2";
    public static final String COLUMN_NAME_DUEDATE = "duedate";
    public static final String COLUMN_NAME_DUETIME = "duetime";
    public static final String COLUMN_NAME_TIMESTAMP = "timestamp";
    }
}

DatabaseHelper.java

public class DatabaseHelper extends SQLiteOpenHelper {
    ...
    private static final String SQL_CREATE_ENTRIES =
        "CREATE TABLE IF NOT EXISTS "+ DBContract.DBEntry.TABLE_NAME_USERINPUTS +
            "(" + DBContract.DBEntry.COLUMN_NAME_ID +
            " INTEGER PRIMARY KEY, " +
            DBContract.DBEntry.COLUMN_NAME_CARDNUM +
            " INTEGER," +
            DBContract.DBEntry.COLUMN_NAME_TODO +
            " TEXT," +
            DBContract.DBEntry.COLUMN_NAME_NOTE1 +
            " TEXT," +
            DBContract.DBEntry.COLUMN_NAME_NOTE2 +
            " TEXT," +
            DBContract.DBEntry.COLUMN_NAME_DUEDATE +
            " TEXT," +
            DBContract.DBEntry.COLUMN_NAME_DUETIME +
            " TEXT," +
            DBContract.DBEntry.COLUMN_NAME_TIMESTAMP +
            " INTEGER)";

    **public void deletefromDB(int cardnum)** {
          SQLiteDatabase db = this.getWritableDatabase();
          // Delete the CardView's data row using the integer from cardum.
          db.delete(DBContract.DBEntry.TABLE_NAME_USERINPUTS,
          DBContract.DBEntry.COLUMN_NAME_CARDNUM + "= ?", new String[]{String.valueOf(cardnum)});        
          db.close();
      }
  }

---

我认为您没有将cardnum值从宿主活动/片段传递到对话框，因此您总是尝试删除cardnum=0 因此，解决方案是您应该在一个bundle中传递cardnum，并将其作为对话框中的片段参数传递，然后在onCreateView（）中获取值。 在其中启动对话框片段并添加以下内容

Bundle args = new Bundle();
args.putInt("cardnum", cardnum);
myFragment.setArguments(args);

在您的onCreateView（）中

---

好的，我会尝试一下。运气不好，数据行仍然存在。@Hack-R我应该删除“SQLiteDatabase db=this.getWritableDatabase（）；好的。将此添加到db.delete:Log.d（“test”，“deleted:+cardnum”）；Ty，我会尝试一下。

public View onCreateView(LayoutInflater inflater, ViewGroup container,
       Bundle savedInstanceState) {

dbHelper = new DatabaseHelper(getActivity());
final View rootView = inflater.inflate(R.layout.delcardview_layout, container, false);
getDialog().setTitle("Delete skycard");
// add this
cardnum = getArguments().getInt("cardnum", 0);
Button btnOK = (Button) rootView.findViewById(R.id.btnOK);
btnOK.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View v) {

        dbHelper.deletefromDB(cardnum);               
        dismiss();
    }
});

return rootView;
}