结果\u错误\u通用\u在android中使用sms管理器发送sms时返回失败

我正在使用短信管理器向多个用户发送短信，但我得到的结果是错误、一般、失败。如何解决这个问题

// ---sends an SMS message to another device---
private void sendSMS(String phoneNumber, String message) {
    String SENT = "SMS_SENT";
    String DELIVERED = "SMS_DELIVERED";

    PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(
            SENT), 0);

    PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
            new Intent(DELIVERED), 0);

    // ---when the SMS has been sent---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS sent",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                Toast.makeText(getBaseContext(), "Generic failure",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NO_SERVICE:
                Toast.makeText(getBaseContext(), "No service",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NULL_PDU:
                Toast.makeText(getBaseContext(), "Null PDU",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_RADIO_OFF:
                Toast.makeText(getBaseContext(), "Radio off",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(SENT));

    // ---when the SMS has been delivered---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            case Activity.RESULT_CANCELED:
                Toast.makeText(getBaseContext(), "SMS not delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(DELIVERED));

    SmsManager sms = SmsManager.getDefault();
    sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
}

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在这里，我使用SmsManager和sendSms（）将数字和消息作为参数。

可能是您应该缩短您的短信正文，以仅容纳1条短信（仅160个字符），我使用了相同的代码并得到了完全相同的错误&当我将短信缩短到160以下时，已成功发送：）

如果您的邮件正文包含超过160个字符，则需要将短信作为多部分发送

如果短信太长，您可以将其拆分并作为部分发送：

            val messageToSend = ...
            val smsManager = SmsManager.getDefault()
            val parts = smsManager.divideMessage(messageToSend)
            for (number in smsNumbersToSend)
                smsManager.sendMultipartTextMessage(number, null, parts, null, null)

---

发布你的日志和相关代码。我在@shayanpourvatan上面添加了源代码。你是在手机上还是在模拟器中发现这个错误的？一般的_故障通常与一些内部无线电问题有关。你是在真实的手机上还是在模拟器上测试的？你得到了这个错误吗？我在MOBILE@shayanpourvatan中测试过。问题是人们确实想发送160多个字符的信息