Android 如何获取AutoCompleteTextView的id?
我有两个autocompletetextview,在我的第一个AutoComplete中,我从服务器得到响应Android 如何获取AutoCompleteTextView的id?,android,json,android-edittext,Android,Json,Android Edittext,我有两个autocompletetextview,在我的第一个AutoComplete中,我从服务器得到响应 {"status":"success","clientlist":[{"cid":"1","name":"margi"},{"cid":"2","name":"steven"}],"productboxtype":[{"pbxid":"1","pbxname":"1 Dozen","qtyperbox":"12"},{"pbxid":"2","pbxname":"2 Dozens
{"status":"success","clientlist":[{"cid":"1","name":"margi"},{"cid":"2","name":"steven"}],"productboxtype":[{"pbxid":"1","pbxname":"1 Dozen","qtyperbox":"12"},{"pbxid":"2","pbxname":"2 Dozens","qtyperbox":"24"},{"pbxid":"3","pbxname":"3 Dozens","qtyperbox":"36"}]}
我可以在我的第一个自动完成中获得姓名,而且效果很好
现在的问题是假设用户选择项“margi”,其cid为1,所以我再次向服务器发送请求,并尝试获取“margi”的产品名称,其响应为
{"status":"success","clientproduct":[{"pid":"4","name":"kangan pair","unitprice":"1500","boxqty":"1"}]}
但在选择了史蒂文之后,第二次自动完成仍然显示了坎甘·帕里
@Override
protected String doInBackground(String...args) {
//Check for success tag
//int success;
Looper.prepare();
try {
JsonParseClientList jp=new JsonParseClientList();
List<NameValuePair> params = new ArrayList<NameValuePair>();
List<SuggestGetSetClientList> list =jp.getParseJsonWCF(acTextView.getText().toString());
for(int i = 0;i<list.size();i++)
{
if(list.get(i).getName().equals(acTextView.getText().toString()))
params.add(new BasicNameValuePair("cid",list.get(i).getId()));
// catid=list.get(i).getId();
}
for(int b=0;b<list.size();b++)
{
catidtemp=list.get(b).id.toString();
System.out.println("cattttttiiiiddd????"+catidtemp);
break;
}
//catidtemp=String.valueOf(selected_cid);
System.out.println("cattttttiiiiddd????"+catidtemp);
params.add(new BasicNameValuePair("action", "clientproduct"));
System.out.println("su gayu server ma????"+params);
Log.d("request!", "starting");
// getting product details by making HTTP request
JSONObject json = jsonParser.makeHttpRequest (
FEEDBACK_URL, "POST", params);
//check your log for json response
Log.d("Login attempt", json.toString());
return json.getString(FEEDBACK_SUCCESS);
}catch (JSONException e) {
e.printStackTrace();
}
return null;
}
// After completing background task Dismiss the progress dialog
protected void onPostExecute(String file_url) {
//dismiss the dialog once product deleted
pDialog.dismiss();
//parentcat.getText().clear();
}}
@覆盖
受保护的字符串doInBackground(字符串…args){
//检查成功标签
//成功;
Looper.prepare();
试一试{
JsonParseClientList jp=新的JsonParseClientList();
List params=new ArrayList();
List List=jp.getParseJsonWCF(acTextView.getText().toString());
对于(int i=0;i如果要比较“boxqty”和“minimum_qty”,在If条件下,不应使用它。length()用于boxqty,因为它只计算字符串的长度,用户将输入,而不是它的值。我认为当您选择“steven”时您得到的响应是clientproduct数组null。这就是为什么会调用catch块,而seconds autocomplete数组不清晰的原因。这就是为什么您在第二个autocomplete中得到上一个值
希望您能理解:)
快乐编码:)
为了不使代码检查复杂化,请查找一些更好地解释用法的教程
另外,如果您更改了适配器信息,请不要忘记呼叫:
adapter.notifyDataSetChanged();
public class Client{
int id;
String name;
//getter and setter for this + constructor;
}
adapter.notifyDataSetChanged();