Android 未显示react本机sqllite值
这是getDetails()Android 未显示react本机sqllite值,android,ios,react-native,sqlite,react-native-sqlite-storage,Android,Ios,React Native,Sqlite,React Native Sqlite Storage,这是getDetails() getDetails=()=>{ 让userDetails=[]; 数据库事务((tx)=>{ tx.executeSql('从角色=?'的用户中选择*,['学生],(tx,结果)=>{ 让详细信息=[] 如果(results.rows.length>0){ for(设i=0;i
getDetails=()=>{
让userDetails=[];
数据库事务((tx)=>{
tx.executeSql('从角色=?'的用户中选择*,['学生],(tx,结果)=>{
让详细信息=[]
如果(results.rows.length>0){
for(设i=0;i
在上面的代码片段中,我能够在tx.executeSql中获取数据(userDetails),但不能在db.transaction块之外
任何人都可以帮助我如何显示db.transaction块之外的数据。定义一个promise函数,用于从db获取
用户详细信息
async dbAction = () => {
return new Promise((resolve, reject) => {
db.transaction((tx) => {
tx.executeSql('select * from users where role=?',['students'],(tx,results) => {
let details = []
if(results.rows.length > 0){
for(let i=0; i < results.rows.length; i++){
details.push(results.rows.item(i));
}
}
//Data is displayed here
resolve(details);
})
})
});
}
嘿,非常感谢。你救了我一天,也减少了我的努力。再次感谢。
async dbAction = () => {
return new Promise((resolve, reject) => {
db.transaction((tx) => {
tx.executeSql('select * from users where role=?',['students'],(tx,results) => {
let details = []
if(results.rows.length > 0){
for(let i=0; i < results.rows.length; i++){
details.push(results.rows.item(i));
}
}
//Data is displayed here
resolve(details);
})
})
});
}
getDetails = () => {
let userDetails = [];
try {
let userDetails = await dbAction();
console.log(userDetails);
} catch (e) {
}
}