Sqlite Android db没有更新或删除FTS?
嘿,所以我使用FTS3和Sqlite来更快地搜索我的android应用程序,然而,当我编辑一个单词或删除一个单词时,它在我的真实db上发生得很好,但在FTS上,什么也没有发生 当我搜索名称pre-edit/update或post-delete时,它仍然显示,这意味着它在数据库中 不确定哪里出了问题,或者如果我必须以另一种方式处理,以下是我的代码:Sqlite Android db没有更新或删除FTS?,android,database,sqlite,full-text-search,Android,Database,Sqlite,Full Text Search,嘿,所以我使用FTS3和Sqlite来更快地搜索我的android应用程序,然而,当我编辑一个单词或删除一个单词时,它在我的真实db上发生得很好,但在FTS上,什么也没有发生 当我搜索名称pre-edit/update或post-delete时,它仍然显示,这意味着它在数据库中 不确定哪里出了问题,或者如果我必须以另一种方式处理,以下是我的代码: /* * deleting all words from dictionary */ public void delete
/*
* deleting all words from dictionary
*/
public void deleteAllWords(DatabaseWords db_delete) {
Log.d("enter delete in dbhelper",
"enter delete in dbhelper "
+ String.valueOf(db_delete.get_id()));
SQLiteDatabase db = this.getWritableDatabase();
db.delete(TABLE_WORDS, KEY_DICTIONARYID + "=?",
new String[] { String.valueOf(db_delete.get_dictionaryId()) });
}
/*
* deleting all words FTS from dictionary
*/
public void deleteAllWords_fts(DatabaseWordsFTS db_delete) {
SQLiteDatabase db = this.getWritableDatabase();
db.delete(
TABLE_WORDS_FTS,
KEY_DICTIONARY_ID_FTS + "=?",
new String[] { String.valueOf(db_delete.get_dictionary_id_fts()) });
}
/*
*
*
* /* deleting a dictionary
*/
public void deleteDictionary(DatabaseDictionary dictionary) {
SQLiteDatabase db = this.getWritableDatabase();
db.delete(TABLE_DICTIONARY, KEY_ID + "=?",
new String[] { String.valueOf(dictionary.get_id()) });
}
/*
* deleting a word
*/
public void deleteWord(DatabaseWords db_delete) {
Log.d("enter delete in dbhelper",
"enter delete in dbhelper "
+ String.valueOf(db_delete.get_id()));
SQLiteDatabase db = this.getWritableDatabase();
db.delete(TABLE_WORDS, KEY_ID + "=?",
new String[] { String.valueOf(db_delete.get_id()) });
}
/*
* deleting a word FTS
*/
public void deleteWord_fts(DatabaseWordsFTS db_delete) {
SQLiteDatabase db = this.getWritableDatabase();
db.delete(TABLE_WORDS_FTS, KEY_ID + "=?",
new String[] { String.valueOf(db_delete.get_id()) });
}
/*
* updating a word
*/
public int updateWord(DatabaseWords word) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_DICTIONARYID, word.get_dictionaryId());
values.put(KEY_WORD1, word.get_word1());
values.put(KEY_WORD2, word.get_word2());
values.put(KEY_WORD3, word.get_word3());
values.put(KEY_WORD4, word.get_word4());
// updating row
return db.update(TABLE_WORDS, values, KEY_ID + "=?",
new String[] { String.valueOf(word.get_id()) });
}
/*
* updating a word FTS
*/
public int updateWord_fts(DatabaseWordsFTS word_fts) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_DICTIONARY_ID_FTS, word_fts.get_dictionary_id_fts());
values.put(KEY_WORD1_FTS, word_fts.get_word1_fts());
values.put(KEY_WORD2_FTS, word_fts.get_word2_fts());
values.put(KEY_WORD3_FTS, word_fts.get_word3_fts());
values.put(KEY_WORD4_FTS, word_fts.get_word4_fts());
// updating row
return db.update(TABLE_WORDS_FTS, values, KEY_ID + "=?",
new String[] { String.valueOf(word_fts.get_id()) });
}
我把常规的那个放在上面,它可以工作,有FTS的那个就是FTS的那个
在这里,我添加了活动文件中的更新代码
// store in db
// creating word
DatabaseWords db_update = new DatabaseWords(word_id, word_d_id,
w_1_s, w_2_s, w_3_s, w_4_s);
DatabaseWordsFTS db_w_fts = new DatabaseWordsFTS(word_id,
word_d_id, w_1_s, w_2_s, w_3_s, w_4_s);
// insert into db create method in database helper
db.updateWord(db_update);
db.updateWord_fts(db_w_fts);
单词更新,但fts one不更新?您不能使用where子句中的数值查询/更新/删除fts表中的行。它只适用于文本。但可以将其转换为一个数字:
SELECT * FROM fts_table WHERE CAST(id AS NUMERIC) = 69
您是否在更新其他表之后更新fts表?我看不到你调用updateWord_fts(…)的任何地方,我只是在上面添加了它,但是单词one updates和传入的内容是correct检查update方法的返回值。看看更新是否真的通过了。还要检查insert和delete,可能您的虚拟表是只读的…它没有执行,如何将其从只读更改为只读?我在android代码中使用了fts4,但从未尝试对其执行任何更新。尝试使用firefox sqlite加载项运行查询。我的意思是在外部创建表,然后对其运行查询。查看您的更新查询是否正确。