Android 无法从可运行转换为线程
我收到这个错误消息“无法从可运行转换为线程”,这是针对威胁T=new Runnable(r)出现的 这是我的密码Android 无法从可运行转换为线程,android,multithreading,textview,delay,runnable,Android,Multithreading,Textview,Delay,Runnable,我收到这个错误消息“无法从可运行转换为线程”,这是针对威胁T=new Runnable(r)出现的 这是我的密码 final String[] texts = new String[]{player, player11, player111}; //etc final Runnable r = new Runnable(){ public void run(){ for(final int i=0;i
final String[] texts = new String[]{player, player11, player111}; //etc
final Runnable r = new Runnable(){
public void run(){
for(final int i=0;i<texts.length;i++){
synchronized(this){
wait(30000); //wait 30 seconds before changing text
}
//to change the textView you must run code on UI Thread so:
runOnUiThread(new Runnable(){
public void run(){
TextView t = (TextView) findViewById(R.id.textView1);
t.setText(texts[i]);
}
});
}
}
};
Thread T = new Runnable(r);
T.start();
final String[]text=新字符串[]{player,player11,player111}//等
最终可运行r=新可运行(){
公开募捐{
对于(final int i=0;i线程
实现可运行
,而不是相反。您的代码中有一行错误的代码
改变
Thread T = new Runnable(r);
到
Sherif是对的。我还建议进行一些代码清理,以避免所有的可运行程序和线程。只需使用处理程序进行更新,并在当前更新30秒后请求另一次更新。这将在UI线程上处理
TextView t;
Handler handler;
int count = 0;
@Override
public void onCreate(Bundle bundle)
{
t = (TextView) findViewById(R.id.textView1);
Handler handler = new Handler();
handler.post(uiUpdater);
}
Runnable uiUpdater = new Runnable()
{
@Override
public void run()
{
count = (count + 1) % texts.length;
t.setText(texts[count]);
handler.removeCallbacks(uiUpdater);
handler.postDelayed(uiUpdater, 30000);
}
};
那我怎么才能修好呢?我是个业余爱好者
TextView t;
Handler handler;
int count = 0;
@Override
public void onCreate(Bundle bundle)
{
t = (TextView) findViewById(R.id.textView1);
Handler handler = new Handler();
handler.post(uiUpdater);
}
Runnable uiUpdater = new Runnable()
{
@Override
public void run()
{
count = (count + 1) % texts.length;
t.setText(texts[count]);
handler.removeCallbacks(uiUpdater);
handler.postDelayed(uiUpdater, 30000);
}
};