Android通过服务中的地理编码器获取位置地址

我跟着去得到位置坐标和地址

所以这里它每10秒更新一次位置坐标纬度和经度

我正试图得到他们的地址

这里是我使用的班级地址

但在这里，它显示的是什么？没有人能告诉我这有什么问题。

您的代码是完美的

在您的

常量类中尝试此操作

strReturnedAddress .append(returnedAddress.getAddressLine(0)).append("\n");

如果您想使用邮政编码、地区和国家。。等使用

List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null) {
    Address returnedAddress = addresses.get(0);
    StringBuilder strReturnedAddress = new StringBuilder("");
    for (int i = 0; i < returnedAddress.getMaxAddressLineIndex(); i++) {
                  strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
    }
        strReturnedAddress .append(returnedAddress.getAddressLine(0)).append("\n");
        strReturnedAddress .append(returnedAddress.getLocality()).append("\n");
        strReturnedAddress .append(returnedAddress.getPostalCode()).append("\n");
        strReturnedAddress .append(returnedAddress.getCountryName());
    strAdd  = strReturnedAddress.toString();
    Log.v("My Current location add", "" + streturnedAddressd.toString());
}

List
您是否尝试使用thread.sleep？原因获取位置和地址可能有点耗时。或者你可以先获取位置值，然后调用地址方法吗？我用了30/60秒的时间尝试了同样的方法，但都是一样的。。
strReturnedAddress .append(returnedAddress.getAddressLine(0)).append("\n");

List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null) {
    Address returnedAddress = addresses.get(0);
    StringBuilder strReturnedAddress = new StringBuilder("");
    for (int i = 0; i < returnedAddress.getMaxAddressLineIndex(); i++) {
                  strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
    }
        strReturnedAddress .append(returnedAddress.getAddressLine(0)).append("\n");
        strReturnedAddress .append(returnedAddress.getLocality()).append("\n");
        strReturnedAddress .append(returnedAddress.getPostalCode()).append("\n");
        strReturnedAddress .append(returnedAddress.getCountryName());
    strAdd  = strReturnedAddress.toString();
    Log.v("My Current location add", "" + streturnedAddressd.toString());
}