Android 字节数组到字符串直到'\n'；

我有Android Arduino蓝牙通信。有时安卓会收到两条信息，而不是来自Arduino的一条。我的意思是：如果我通过蓝牙从Arduino向Android发送例如5字节的消息“1234”，有时我在一条消息中得到“1”1字节，在第二条消息中得到“234”+\n 4字节。有时我会收到完整的“1234”+\n 5字节消息，但不知道原因。我需要按分隔符分割输入消息，若我得到单独的消息，我会崩溃。所以我需要在字符串中添加字节，直到新行char出现

• 如何向字符串添加字符，直到“\n”新行字符出现

数据出现时的情况：

    case BLUETOOTH_RECEIVED:
        byte[] buffer = (byte[])msg.obj;
        int len = msg.arg1;
        if (len > 0 && buffer != null) {
            onBluetoothRead(buffer, len);
        }
        break;
    }

缓冲区到字符串：

private void onBluetoothRead(byte[] buffer, int len) {
    Log.i(LOGGER_TAG, String.format("Received: " +  output.replace("\n", "") + " message of " + "%d bytes", len));
    String output = new String(buffer, 0, len); // Add read buffer to new string
    m_deviceOutput.append(output); // Add (not replace) string to TextView
    StringTokenizer  splitStr = new StringTokenizer(output, ","); // split string by comma
    String numberOne = splitStr.nextToken(); // First split string
    String numberTwo = splitStr.nextToken(); // Second split string
    numberOne = numberOne.replaceAll("\\D+",""); // replace all chars, leave only numbers
    numberTwo = numberTwo.replaceAll("\\D+","");
}

日志：

07-22 14:06:15.099: I/DeviceActivity(20370): Received: 1234 message of 5 bytes
07-22 14:06:20.599: I/DeviceActivity(20370): Received: 1234 message of 5 bytes
07-22 14:06:27.349: I/DeviceActivity(20370): Received: 1 message of 1 bytes
07-22 14:06:27.469: I/DeviceActivity(20370): Received: 234 message of 4 bytes
07-22 14:06:37.219: I/DeviceActivity(20370): Received: 1 message of 1 bytes
07-22 14:06:37.349: I/DeviceActivity(20370): Received: 234 message of 4 bytes

在Arduino中，我可以这样写，我希望这里有类似的东西：

//Get data from RS485:
void READ01(){
  while (mySerial.available()){
    mySerial.read();
  }
    mySerial.println("01READ");
    momentas1="";
    delay(20);

    while (mySerial.available()) { 
      char c = mySerial.read();
      if (c == '\n'){
     break;
      }
      momentas1 += c; 
      }
}

---

此

void READ01

将字符添加到字符串中，直到新行字符出现。

您可以使用类似缓冲区的实现，将获得的字符串添加到另一个字符串中，直到收到“\n”

private String packet = "";
private void onBluetoothRead(byte[] buffer, int len) {
    Log.i(LOGGER_TAG, String.format("Received: " +  output.replace("\n", "") + " message of " + "%d bytes", len));
    String output = new String(buffer, 0, len); // Add read buffer to new string
    packet += output;
    if (packet.endsWith( "\n" ) {
        //do what you need to do
        m_deviceOutput.append(output); // Add (not replace) string to TextView
        StringTokenizer  splitStr = new StringTokenizer(packet, ","); // split string by comma
        String numberOne = splitStr.nextToken(); // First split string
        String numberTwo = splitStr.nextToken(); // Second split string
        numberOne = numberOne.replaceAll("\\D+",""); // replace all chars, leave only numbers
        numberTwo = numberTwo.replaceAll("\\D+","");
        packet = "";
    }

}

---

我不知道

string.endsWith（）

。。。我会尝试，但我相信99.9%的人认为这是一个答案：）你好，我希望它能奏效。但请注意，我已进行了编辑。我写的代码中有一个错误。最初在为Eclipse编写代码时，我更正了它：）谢谢你，Ruraj:）

。StartWith（）

和

。endsWith（）

非常有用：）很高兴能帮上忙：）