Android-无法从url字符串打开浏览器意图

Android-无法从url字符串打开浏览器意图,android,android-intent,android-browser,intentservice,Android,Android Intent,Android Browser,Intentservice,我正在处理XML并收集URL作为字符串变量。我得到了正确的链接,我可以在LogCat中设置它 然而,当我建立了一个监听器;它无法识别链接并引发ActivityNotFoundException 这是代码 @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); final String announcementsTitle="announcem

我正在处理XML并收集URL作为字符串变量。我得到了正确的链接,我可以在LogCat中设置它

然而,当我建立了一个监听器;它无法识别链接并引发ActivityNotFoundException

这是代码

@Override
public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);

    final String announcementsTitle="announcements";
    final String announcementsLink = "link";

    ArrayList<HashMap<String, String>> announcementsList = new ArrayList<HashMap<String, String>>();

    try
    {

        URL url = new URL("http://www.myexperiment.org/announcements.xml?num=100&order=reverse");

        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();

        Document doc = db.parse(new InputSource(url.openStream()));
        doc.getDocumentElement().normalize();

        NodeList nodeList1 = doc.getElementsByTagName("announcement");


        for(int i=0; i < nodeList1.getLength(); i++)
        {
            //Creating HashMap
            HashMap<String, String> map = new HashMap<String, String>();

            Node node = nodeList1.item(i);

            //For the announcement title
            Element firstElement = (Element) node;
            NodeList nameList = firstElement.getElementsByTagName("announcement");

            Element nameElement = (Element) nameList.item(0);
            nameList = nameElement.getChildNodes();

            String link1 = firstElement.getAttributeNode("resource").getNodeValue();


            //Adding values of each into HashMap
            map.put(announcementsTitle,((Node) nameList.item(0)).getNodeValue());
            map.put(announcementsLink,link1);

            String title = nameList.item(0).getNodeValue();


            Log.d("Announcements: ", title);
            Log.d("Link: ", link1);

            //Adding HashList to ArrayList
            announcementsList.add(map);

        }//for

        ListAdapter adapter = new SimpleAdapter(this, announcementsList,R.layout.announcements,
                                 new String[] {announcementsTitle, announcementsLink}, 
                                 new int[] {R.id.announcementTitle});
        setListAdapter(adapter);

        ListView lv = getListView();

        lv.setOnItemClickListener(new OnItemClickListener()
        {

            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) 
            {

                //String the new Intent open the browser with link
                Log.d("Link: ", announcementsLink);

                final Intent announcementsIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(announcementsLink));
                startActivity(announcementsIntent);
            }

        });

    }
    catch(Exception e)
    {
        System.out.println("XML Parsing Exeption = " + e);
    }

}//onCreate

您正在将
announcementsLink
变量的值作为URI传递给startActivity。此变量的值是并且将始终是
“link”
。这不是有效的URI。我猜您想做的是获取与单击的ListItem关联的URI,而您没有这样做。您可以获取为特定列表项存储的链接,如下所示:

lv.setOnItemClickListener(new OnItemClickListener()
{
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) 
    {
        final String itemLink = adapter.getItem(potition).get(announcementsLink)
        final Intent announcementsIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(itemLink));
        startActivity(announcementsIntent);
    }
});
lv.setOnItemClickListener(新的OnItemClickListener()
{
@凌驾
public void onItemClick(AdapterView父对象、视图、整型位置、长id)
{
最后一个字符串itemLink=adapter.getItem(potition.get)(announcementsLink)
final Intent announcementsinent=新意图(Intent.ACTION_视图,Uri.parse(itemLink));
startActivity(公告);
}
});

免责声明,我自己还没有测试过这段代码,但总体思路是这样的。

谢谢您的回复。我做了你建议的合乎逻辑的改变。但是,出现了一个错误。它说itemLink必须是最终的,也就是说。但随后它也要求公告链接成为最终链接;如果我将其设置为final,那么它会抛出错误,使itemLink仅为string而不是final string。请尝试将announcementsLinks和announcmentTitles移出onCreate方法。只需将它们设置为类中的私有静态最终变量。
lv.setOnItemClickListener(new OnItemClickListener()
{
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) 
    {
        final String itemLink = adapter.getItem(potition).get(announcementsLink)
        final Intent announcementsIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(itemLink));
        startActivity(announcementsIntent);
    }
});