android蓝牙应用程序在通话过程中无响应
我有一个通过异步任务与蓝牙设备通信的应用程序 如果我接到一个电话,在通话中我会返回应用程序 屏幕变暗,应用程序无响应 后退按钮不起作用。。。并且不显示ANR对话框 有什么想法吗 以下是处理连接的代码:android蓝牙应用程序在通话过程中无响应,android,bluetooth,Android,Bluetooth,我有一个通过异步任务与蓝牙设备通信的应用程序 如果我接到一个电话,在通话中我会返回应用程序 屏幕变暗,应用程序无响应 后退按钮不起作用。。。并且不显示ANR对话框 有什么想法吗 以下是处理连接的代码: @Override protected Object doInBackground(Object... params) { //boolean protocolUpdated; int read = 0; /
@Override
protected Object doInBackground(Object... params) {
//boolean protocolUpdated;
int read = 0; // The amount of bytes read from the socket.
byte[] buff = new byte[MessageHandler.BUFFERSIZE]; // The data buffer.
byte[] tmpSend = null; // Misc bytes arrays returned from ProtocolParser as answers to send after decoding calls.
in = null;
out = null;
try {
if (Float.parseFloat(version) > 2.2){
Method m = dev.getClass().getMethod("createRfcommSocket", new Class[] {int.class});
sock = (BluetoothSocket) m.invoke(dev, 1);
}
else sock = dev.createRfcommSocketToServiceRecord(UUID_RFCOMM_GENERIC); // UUID is constant for serial BT devices.
sock.connect(); // connect to the BT device. This is rather heavy, may take 3 secs.
sendMessage(MESSAGE_CONNECTION_ESTABLISHED);
in = sock.getInputStream();
out = sock.getOutputStream();
timer = new Timer();
startFinishTimer(); //initialize finish timer
while(read != -1) { // read = -1 means EOF.
do { // as long as there is anything to send in the send queue - send it.
tmpSend = parser.nextSend();
if(tmpSend != null){
String msg = parseMessage(tmpSend);
Log.d("Writing:",msg);
out.write(tmpSend);
}
} while(tmpSend != null);
read = in.read(buff); // read. This is a blocking call, to break this, interrupt the thread.
timer.cancel();
startFinishTimer(); //read is a blocking call so timer should be restarted only after read bytes.
parser.parse(buff,read); // parse the read message using the logic in the ProtocolParser derived class.
tmpSend = parser.getPool(); // if pool ack is required - send it.
if (tmpSend != null){
Log.d("Writing:",parseMessage(tmpSend));
out.write(tmpSend);
}
if (read != 0){
Log.d("Read:",parseMessage(buff));
tmpSend = parser.getAnswer(); // if answer is required (based on message) - send it.
if(tmpSend != null){
out.write(tmpSend);
}
}
else {
Exception e = new IOException();
throw e;
}
}
}catch (IOException e){
e.printStackTrace();
Log.d("Connection: ", "Bluetooth Connection CRASHED!");
sendMessage(MESSAGE_CONNECTION_LOST);
}catch (Exception e){
e.printStackTrace();
}
return null;
}
事实上,没有足够的背景来发现你的问题 确保您从主线程启动此任务,否则PostExecute将连接到错误的线程,您可能会遇到竞争 确保在代码中不向多个处理程序发送相同的消息。 消息是一个链表,在这种情况下,您可能会得到ANR 获取/data/anr/traces.txt以确保它不是anr
您可以在文件开头确定时间。实际上没有足够的上下文来查找您的问题 确保您从主线程启动此任务,否则PostExecute将连接到错误的线程,您可能会遇到竞争 确保在代码中不向多个处理程序发送相同的消息。 消息是一个链表,在这种情况下,您可能会得到ANR 获取/data/anr/traces.txt以确保它不是anr
您可以在文件的开头确定时间。谢谢您的回复,谢尔盖。我不确定你是否注意到了,但这个问题是在大约两年前提出的。可悲的是,这个项目已经完成了一段时间,说实话,我甚至都不记得到底是什么问题……谢谢你的回复,谢尔盖。我不确定你是否注意到了,但这个问题是在大约两年前提出的。可悲的是,这个项目已经完成了一段时间,说实话,我甚至都不记得到底是什么问题。。。